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alex41 [277]
2 years ago
10

What can be said about a reaction with AH= 62.4 kJ/mol and AS= 0.145

Chemistry
1 answer:
seropon [69]2 years ago
6 0

Answer:

<em>B.</em><em> </em><em>It </em><em>is </em><em>spontaneous </em><em>at </em><em>5</em><em>0</em><em>0</em><em>k</em><em> </em>

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What is the mass of 3.8 × 10^24 atoms of argon (ar)? 0.0039 g 0.16 g 6.3 g 250 g
ale4655 [162]
Atomic mass Ar => 39.948 a.m.u

39.948 g --------------- 6.02x10²³ atoms
?? g -------------------- 3.8x10²⁴ atoms

(3.8x10²⁴) x 39.948 / 6.02x10²³ => 250 g

hope this helps!

5 0
3 years ago
Read 2 more answers
What should you do if the high power objective lens touches or breaks the cover slip?
saul85 [17]
Tell your teacher. They'll know what to do and it's best to report it to them.
6 0
3 years ago
How did the pH level and the water components level change after adding water to the battery acid?
ololo11 [35]
The pH level changed to 1.34 and the combination of the both made the mixture less acidic
the pH is 1.84, mixture had less acid and there is alot more water molecules in the mixture
the pH level is 2.13 ,, again less acidic and the water molecules has increased to 3,28 x10(25)
7 0
3 years ago
How much faster does ethane (C2H6) gas travel compared to chlorine gas?
zimovet [89]

Answer:

\large \boxed{\text{54 $\, \%$ faster }}

Explanation:

v_{\text{rms}} \propto \sqrt{\dfrac{3RT}{M}

if temperature is constant.  

v_{\text{rms}} \propto \sqrt{\dfrac{1}{M}

if we are comparing two gases,

\dfrac{v_{2}}{v_{1}} = \sqrt{\dfrac{M_{1}}{M_{2}}}

Let chlorine be Gas 1 and ethane be Gas 2

Data:

M₁ =  70.91 g/mol

M₂ = 30.07 g/mol

Calculation

\begin{array}{rcl}\dfrac{v_{2}}{v_{1}} & = & \sqrt{\dfrac{M_{1}}{M_{2}}}\\\\& = & \sqrt{\dfrac{70.91}{30.07}}\\\\& = & \sqrt{2.358}\\\\& = & \mathbf{1.54}\\\end{array}\\\text{Ethane molecules travel at 1.54 times the speed of chlorine molecules}\\\text{or $\large \boxed{\textbf{54 $\%$ faster }}$ than chlorine molecules}

5 0
2 years ago
5.2 X 1026 molecules of CH4
olya-2409 [2.1K]

<h3 /><h3><u>Answer</u><u> </u><u>above</u><u> </u></h3>

<u>I</u><u> </u><u>cant</u><u> </u><u>send</u><u> </u><u>this</u><u> </u><u>with</u><u> </u><u>no</u><u> </u><u>text</u><u> </u>

<u>Have</u><u> </u><u>a</u><u> </u><u>nice</u><u> </u><u>day</u>

8 0
2 years ago
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