Sorry but I only know a few
17- decomposers
18- decomposition
21- 10% is lost so 90%
The reaction is:
6 Cr²⁺ + Cr₂O₇²⁻ + 14 H⁺ → 8 Cr³⁺ + 7 H₂O
E₀ = 1.33 - (-0.5) = 1.83 V
ΔG = - n f E₀
= - 6 * 96485 * 1.83
= - 1059405.3 J / mol
= - 1059.4 kJ / mol
1. Answer;
=56 g/mol
Explanation and solution;
PV = nRT
nRT= mass/molar mass (RT)
molar mass = (mass/V ) × (RT/P)
= Density × (RT/P)
Molar mass = 2.0 g/L × (0.0821 × 323 K)/0.948 atm
Molar mass = 56 g/mol
2. Answer;
Molecular mass is C4H8
Explanation;
Empirical mass × n = molar mass
Empirical mass for CH2 = 14 g/mol
Therefore;
56 g/mol = 14 g/mol × n
n = 4
The molecular formula= 4(CH2)
= C4H8
Answer:Noble gases:
are highly reactive.
react only with other gases.
do not appear in the periodic table.
are not very reactive with other elements.
Explanation:Noble gases:
are highly reactive.
react only with other gases.
do not appear in the periodic table.
are not very reactive with other elements.
The answer is (3) Cu2O. Copper (I) has an oxidation state of +1 (that's what the "I" indicates). You can also think of this as copper (I) having a charge of +1. Oxygen has an oxidation state of -2 (that's just a rule you have to know), and you can think of it as oxygen having a charge of -2. You need oxidation numbers in a neutral compound to add up to 0 (or charges in a neutral compond to add up to 0), so you need two Cu to balance the O, which is Cu2O.