Answer:
0.00500M of Na₂C₂O₄
Explanation:
<em>When are dissolved in 150 mL of 1.0 M H2SO4.</em>
<em />
We can solve this problem finding molarity of sodium oxalate: That is, moles of Na2C2O4 per liter of solution. Thus, we need to convert the 0.1005g to moles using molar mass of sodium oxalate (134g/mol) and dividing in the 0.150L of the solution:
0.1005g * (1mol / 134g) = 7.5x10⁻⁴ moles of Na₂C₂O₄
In 0.150L:
7.5x10⁻⁴ moles of Na₂C₂O₄ / 0.150L =
<h3>0.00500M of Na₂C₂O₄</h3>
Answer:
1. Hydrogen ions; acidic
2. Alkali; hydroxide ions; alkaline
3a. Sulfuric acid --> 2 Hydrogen ions + sulfate ion
H₂SO₄ --> 2H+ + SO₄²-
3b. Sodium hydroxide --> Sodium ion + Hydroxide ion
NaOH --> Na+ + OH-
Explanation:
1. Sulfuric acid releases hydrogen ions in solution. This makes the solution acidic.
Acids produce hydrogen ions when dissolved in aqueous solutions.
2. Sodium hydroxide is an alkali. It releases hydroxide ions in solution. This makes the solution alkaline.
Alkalis are soluble bases that produce hydroxide ions in solution.
3a. Sulfuric acid --> 2 Hydrogen ions + sulfate ions
H₂SO₄ --> 2H+ + SO₄²-
The equation above is for the ionization of sulfuric acid
b. Sodium hydroxide --> Sodium ion + Hydroxide ion
NaOH --> Na+ + OH-
The equation above is for the ionization of sodium hydroxide
Answer:
Amylase enzymes help break down starches into sugars/maltose
Explanation: A
Moles of ammonium sulfide = 5.80 mol
The formula of ammonium sulfide is (NH₄)₂S
So each molecule of ammonium sulfide has (4 x 2) or 8 atoms of H
One mole of ammonium sulfide has 8 moles of H
5.80 mol of ammonium sulfide has (8 x 5.8) or 46.4 moles of H
As per the definition of Avogadro's number, 1 mole = 6.022 x 10²³ atoms
46.4 moles of H x (6.022 x 10²³ atoms/ 1 mole of H)
= 2.8 x 10²⁵ H atoms
Therefore, 2.8 x 10²⁵ H atoms are in 5.80 mol of ammonium sulfide.
