Explanation :
As we know that the Gibbs free energy is not only function of temperature and pressure but also amount of each substance in the system.
where,
is the amount of component 1 and 2 in the system.
Partial molar Gibbs free energy : The partial derivative of Gibbs free energy with respect to amount of component (i) of a mixture when other variable 
are kept constant are known as partial molar Gibbs free energy of 
component.
For a substance in a mixture, the chemical potential 
is defined as the partial molar Gibbs free energy.
The expression will be:
where,
T = temperature
P = pressure
is the amount of component 'i' and 'j' in the system.
Using the method chromatography
Im taking lambda as x (wavelength)
m = 0.17 kg
v=37m/s
h=6.62*10^-34m²kg/s
x= h/mv
The second volume : 42.2 L
<h3>Further explanation</h3>
Given
51.7 L at 27 C and 90.9 KPa
Required
The second volume
Solution
STP = P₂=1 atm, T₂=273 K
T₁ = 27 + 273 = 300 K
P₁ = 90.9 kPa = 0,897 atm
Use combine gas law :
P₁V₁/T₁ = P₂V₂/T₂
Input the value :
0.897 x 51.7/300 = 1 x V₂/273
V₂= 42.20 L
The correct Anwser is enzymes
