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2 years ago

What is the volume of the triangular right prism?

Mathematics

1 answer:

Minchanka [31]2 years ago

5 0

Answer:D

Step-by-step explanation:

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What is the greatest common factor of 24s3, 12s4, and 18s?

Paha777 [63]

6s as 6 goes into 24, 12 and 18

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3 years ago

Hi please help i will mark brain list giving all my points

DochEvi [55]

Answer:

Step-by-step explanation:

It looks like addition to me.

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3 years ago

Read 2 more answers

Find the equation of the parabola whose vertex is the origin and whose directrix is x = -4

lapo4ka [179]

Try this option:

1) if V(0;0) and x= -4, then common view of the required equiation is:

(y-k)²=4p(x-h), where focus is in (h-p;k), the vertex is in (h;k), the directrix is x=h+p, p<0 and y=k is simmetry axis;

2) if the V(0;0), then h=k=0 and the required equiation is:

y²=4px;

3) if the directrix equation is x=h+p, where h=0, then p= -4 (according to the condition the directrix equation is x= -4), then the required equation is:

y²= -16x

answer: y²= -16x

6 0

3 years ago

A number cube is rolled twice. What is the probability of getting a 6 on the first roll,

ivann1987 [24]

Answer:

b. 1/9

Step-by-step explanation:

1. 1/6 is the probability of rolling 6

2. 4/6 is the probability of rolling less than 5

3. Multiply them: $\frac{1}{6} x\frac{2}{3}$

4. Answer: 1/9

8 0

2 years ago

Suppose a large shipment of laser printers contained 22% defectives. If a sample of size 276 is selected, what is the probabilit

Mrrafil [7]

Answer:

The probability that the sample proportion will differ from the population proportion by less than 6% is 0.992.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

$\mu_{\hat p}=p\\\\$

The standard deviation of this sampling distribution of sample proportion is:

$\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}$

The information provided is:

$p=0.22\\n=276$

As the sample size is large, i.e. <em>n</em> = 276 > 30, the Central limit theorem can be used to approximate the sampling distribution of sample proportion.

Compute the value of $P(\hat p-p$ as follows:

$P(\hat p-p$

Thus, the probability that the sample proportion will differ from the population proportion by less than 6% is 0.992.

6 0

3 years ago