How many grams are in 6.4 moles of so2

The results of the gold foil experiment led to the conclusion that an atom is

viva [34]

$\sf\large \blue{\underbrace{\red{Answer⋆}}}:$

The nucleus of an atom of the element is positively charged and atom has a hollow space inside it.

Explanation:

This experiment was conducted by Rutherford in this experiment. He placed a gold foil and surround it with a screen.

And He exposed gold foil in alpha particles rays in which he noticed that most rays passed through atom which conclude that atom has a large space, some rays get deflected and some reverse their path this show that the positive charge of nucleus of an atom.

4 0

2 years ago

The DH for the solution process when solid sodium hydroxide dissolves in water is -44.4 kJ/mol. When a 13.9-g sample of NaOH dis

salantis [7]

Answer:

The temperature increases from 23.0 C to 37.0 °C

Explanation:

Step 1: Data given

DH = -44.4 kJ/mol

mass NaOH = 13.9 grams

mass of water = 250.0 grams

Initial temperature = 23°C = 295 K

Final temperature = TO BE DETERMINED

Specific heat = 4.18 J/g*K

Step 2: Calculate change in temperature

13.9 grams/ 40 g/mol * 44.4 kJ/mol = 15429 J

15429 J = (massNaOH + mass water) * 4.18 * ΔT

15429 = 263.9 *4.18 * ΔT

ΔT = 14°C

Step 3: Calculate final temperature

ΔT= 14°C = T2 - 23°C

T2 = 23 +14 = 37 °C

The temperature increases from 23.0 C to 37.0 °C

7 0

3 years ago

Read 2 more answers

6

lakkis [162]

The answer is Move slower I believe

6 0

3 years ago

C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O (l)

vlabodo [156]

Answer:

Approximately $0.254\; \rm L$ (at STP.)

Assumption: both $\rm C_3H_8$ and $\rm CO_2$ act like ideal gases.

Explanation:

Make sure that this chemical equation is properly balanced.

The ratio between the coefficient of $\rm C_3H_8$ and that of $\rm CO_2$ is $1:3$ . As a result, for every $1\; \rm mol$ of $\rm C_3H_8$ consumed, $3\; \rm mol$ of $\rm CO_2$ will be produced.

In other words:

$\displaystyle \frac{n(\mathrm{C_3H_8\, (g)})}{n(\mathrm{CO_2\, (g)})} = \frac{1}{3}$ .

The coefficients in the balanced equation give a relationship between the number of moles of the two species. One more step is required to obtain a relationship between the volume of these two species.

Under the same pressure and temperature, two ideal gases with the same number of gas particles will have the same volume. Additionally, the volume of an ideal gas is proportional to the number of particles in it.

In this question, if both $\rm C_3H_8$ and $\rm CO_2$ are at STP, their pressure and temperature would indeed be the same. If they are both assumed to be ideal gases, then the ratio between their volumes would be the same as the ratio between the number of moles of their particles. that is:

$\displaystyle \frac{V(\mathrm{C_3H_8\, (g)})}{V(\mathrm{CO_2\, (g))}} = \frac{n(\mathrm{C_3H_8\, (g)})}{n(\mathrm{CO_2\, (g)})} = \frac{1}{3}$ .

Therefore, to produce $0.762\; \rm L$ of $\rm CO_2$ , the minimum volume of $\rm C_3H_8$ would be:

$\begin{aligned} &V(\mathrm{C_3H_8\, (g))} \\ &= \frac{V(\mathrm{C_3H_8\, (g)})}{V(\mathrm{CO_2\, (g))}} \cdot V(\mathrm{CO_2\, (g))} \\ &= \frac{1}{3} \times 0.762\; \rm L\end{aligned}$ .

3 0

3 years ago

Consider Zn + 2HCl → ZnCl2 + H2 (g). If 0.30 mol Zn reacts with HCl, how many grams of HCl are needed?

Studentka2010 [4]

Answer:

22 grams

Explanation:

Zn + 2HCl → ZnCl2 + H2

The first step to answering this question is to calculate the amount of moles of HCl needed. We do this by multiplying the coefficient of HCl in the equation over the coefficient of Zn.

0.30mol × $\frac{2}{1}$ = 0.60 mol HCl

Now, to figure out how many grams we must multiply the amount of moles of HCl by it's molar mass. This molar mass can be found by adding the molar masses of all the elements in HCl.

0.60mol × 36.46 g/mol = 21.87g

Using proper sig figs, 22 grams of HCl are required for this reaction.

6 0

3 years ago