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ANTONII [103]
3 years ago
9

An unknown substance is made only of identical atoms that cannot be broken down. This substance is a ________.

Chemistry
2 answers:
kherson [118]3 years ago
8 0

Answer: Element

Explanation:

Element is a pure substance which is composed of identical atoms. It can not be decomposed into simpler constituents using chemical reactions.Example: Silver (Ag)

Compound is a pure substance which is made from atoms of different elements combined together in a fixed ratio by mass.It can be decomposed into simpler constituents using chemical reactions. Example: carbon dioxide (CO_2)

Thus an unknown substance is made only of identical atoms that cannot be broken down is an element.

Veseljchak [2.6K]3 years ago
7 0
The substance is an element off of the periodic table. 
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Why does increasing the temperature of water increase the rate of chemical reaction in the graph
Nady [450]

Answer:

Explanation:

Increasing the temperature increases reaction rates because of the disproportionately large increase in the number of high energy collisions.

Plz mark me brainliest.

8 0
3 years ago
"the osmotic pressure exerted by a solution is equal to the molarity multiplied by the absolute temperature and the gas constant
ASHA 777 [7]

Answer: -

The concentration is 0.91 mol/ L

Explanation: -

The osmotic pressure = 23 atm

Absolute temperature = 309 K

Universal gas constant = 0.08206 L atm mol⁻¹ K⁻¹

We know the formula

Osmotic pressure = molar concentration x universal gas constant x absolute temperature

Plugging in the values

23 atm = molar concentration x 0.08206 L atm mol⁻¹ K⁻¹ x 309 K

Molar concentration = \frac{23}{0.08206 x 309} mol/ L

                                  = 0.91 mol / L

8 0
3 years ago
Read 2 more answers
Ideal gas (n 2.388 moles) is heated at constant volume from T1 299.5 K to final temperature T2 369.5 K. Calculate the work and h
bija089 [108]

Answer : The work, heat during the process and the change of entropy of the gas are, 0 J, 3333.003 J and -10 J respectively.

Explanation :

(a) At constant volume condition the entropy change of the gas is:

\Delta S=-n\times C_v\ln \frac{T_2}{T_1}

We know that,

The relation between the C_p\text{ and }C_v for an ideal gas are :

C_p-C_v=R

As we are given :

C_p=28.253J/K.mole

28.253J/K.mole-C_v=8.314J/K.mole

C_v=19.939J/K.mole

Now we have to calculate the entropy change of the gas.

\Delta S=-n\times C_v\ln \frac{T_2}{T_1}

\Delta S=-2.388\times 19.939J/K.mole\ln \frac{369.5K}{299.5K}=-10J

(b) As we know that, the work done for isochoric (constant volume) is equal to zero. (w=-pdV)

(C) Heat during the process will be,

q=n\times C_v\times (T_2-T_1)=2.388mole\times 19.939J/K.mole\times (369.5-299.5)K= 3333.003J

Therefore, the work, heat during the process and the change of entropy of the gas are, 0 J, 3333.003 J and -10 J respectively.

7 0
3 years ago
The state of the atmosphere at a given time and place is called
s344n2d4d5 [400]

Answer:a

Explanation:

6 0
3 years ago
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How many grams are in 3.14 x 1015 molecules of CO?
Vesnalui [34]

Answer:

Explanation:

Not Many

1 mol of CO has a mass of

C = 12

O = 16

1 mol = 28 grams.

1 mol of molecules = 6.02 * 10^23

x mol of molecules = 3.14 * 10^15        Cross multiply

6.02*10^23 x = 1 * 3.14 * 10^15             Divide by 6.02*10^23

x = 3.14*10^15 / 6.02*10^23

x = 0.000000005 mols

x = 5*10^-9

1 mol of CO has a mass of 28

5*10^-9 mol of CO has a mass of x                        Cross Multiply

x = 5 * 10^-9 * 28

x = 1.46 * 10^-7 grams

Answer: there are 1.46 * 10-7 grams of CO if only 3.14 * 10^15 molecules are in the sample

5 0
2 years ago
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