Answer:
-1.42, -0.375, 32.5% (.325), 3/8 (.375), √4 (2.0), 3 (3.0), 2³ (8.0)
Answer:
Explanation:
= Mass of water = 100 g
= Specific heat of water = 
= Mass of copper = 20 g
= Specific heat of copper = 
= Temperature change in water = 
= Temperature change in cooper = 
T = Final temperature of the system
The heat balance of the system is given by
The final temperature of the water is .
The combines law of gas is:
P1 * V1 P2 * V2
---------- = -----------
T1 T2
So, you can obtain many equivalent valid forms depending on the variable that you solve for.
These are some examples:
Solve for T1:
T1 = T2 * (P1 * V1) / (P2 * V2)
Solve for V2:
V2 = V1 * (T2 / T1) * (P1 / P2)
Solve for P1:
P1 = P2 * (T1 / T2) * ( V2 / V1)
Answer:
1. MgCl2 + Zn -> Mg + ZnCl2
2. 2Al + 6H2O(g) -> 2Al(OH)3 + 3H2
3. 2Cd + O2 -> 2CdO
4. I2 + KF -> it's not going to react
5. Zn + H2SO4 -> ZnSO4 + H2
6.2KBr + Cl2 -> 2KCl + Br2
7. AgNO3 + Na -> NaNO3 + Ag
8. 2NaCl + F2 -> 2NaF + Cl2
9. AgNO3 + Mg(NO3)2 + Ag
10. Ni + H2SO4 -> NiSO4 + H2
11. Al + K2SO4
12. FeCl3 + 3Mn-> 3MnCl + Fe
13. 2Na + 2H2O -> 2NaOH + H2
14. 2K + MgBr2 -> 2KBr + Mg
15. Zn + Pb(NO3)2 -> Pb + Zn(NO3)2
16. 2AlBr3+ 3Cl2 -> 2AlCl3 + 3Br2
