C – coming to
senses and finally realized that everything is dynamic and I should learn to
invest into knowing what of these changes are right or wrong and being
H – hopeful that
someday, these changes will actually make sense and that all of these questions
and confusions will be answered in the right time and the right place. But
whatever happens, I must learn to
A – adapt from
the different things I see everyday, If the world changes for its betterment or
for its worse, then I too, should change as well to go with the flow. However,
keep in mind to
N – never leave
the small things behind because these things when summed up actually what make
sense of everything and could possibly answer the
G – growing dynamics
of the world and its inhabitants. Throughout all this, it is always important
to
<span>
E-educate
yourself, that when the change will finally take effect on you, you will be
ready.</span>
Answer:
Im guessing it's C....................................................
1. Answer;
=56 g/mol
Explanation and solution;
PV = nRT
nRT= mass/molar mass (RT)
molar mass = (mass/V ) × (RT/P)
= Density × (RT/P)
Molar mass = 2.0 g/L × (0.0821 × 323 K)/0.948 atm
Molar mass = 56 g/mol
2. Answer;
Molecular mass is C4H8
Explanation;
Empirical mass × n = molar mass
Empirical mass for CH2 = 14 g/mol
Therefore;
56 g/mol = 14 g/mol × n
n = 4
The molecular formula= 4(CH2)
= C4H8
Answer:
Solid
Explanation:
The particles are densely packed and in a defined shape, therefore they would be defined as a solid.
Answer:
0.924 g
Explanation:
The following data were obtained from the question:
Volume of CO2 at RTP = 0.50 dm³
Mass of CO2 =?
Next, we shall determine the number of mole of CO2 that occupied 0.50 dm³ at RTP (room temperature and pressure). This can be obtained as follow:
1 mole of gas = 24 dm³ at RTP
Thus,
1 mole of CO2 occupies 24 dm³ at RTP.
Therefore, Xmol of CO2 will occupy 0.50 dm³ at RTP i.e
Xmol of CO2 = 0.5 /24
Xmol of CO2 = 0.021 mole
Thus, 0.021 mole of CO2 occupied 0.5 dm³ at RTP.
Finally, we shall determine the mass of CO2 as follow:
Mole of CO2 = 0.021 mole
Molar mass of CO2 = 12 + (2×16) = 13 + 32 = 44 g/mol
Mass of CO2 =?
Mole = mass /Molar mass
0.021 = mass of CO2 /44
Cross multiply
Mass of CO2 = 0.021 × 44
Mass of CO2 = 0.924 g.
