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vovikov84 [41]
1 year ago
7

25. 22 the reaction of phenylmagnesium bromide with methyl benzoate followed by acidification produces triphenylcarbinol. what a

re the sources of phenyl groups in triphenylcarbinol?
Chemistry
1 answer:
ExtremeBDS [4]1 year ago
3 0

Triphenylcarbinol( or triphenylmethanol) gets its phenyl groups from phenylmagnesium bromide.

Synthesis of triphenylcarbinol:

A typical laboratory experiment for demonstrating the Grignard reaction is the synthesis of triphenylmethanol using methyl benzoate, benzophenone, and phenylmagnesium bromide. Diethyl carbonate is a possible starting material.

Characteristics:

  • An organic substance is a triphenylmethanol. It is a white, crystalline substance that dissolves well in alcohol, diethyl ether, and benzene but not in water or petroleum ether. Due to the creation of a persistent "trityl" carbocation, it generates a bright yellow hue in very acidic solutions. Important dyes include several triphenylmethanol derivatives.
  • Triphenylmethanol has a core tetrahedral carbon atom, three phenyls (Ph) rings, and an alcohol group attached to it. With lengths of around 1.47Å for all three C-Ph bonds and 1.42Å for the C-O link, these connections are characteristic of sp3-sp2 carbon-carbon bonds.
  • Three neighboring phenyl groups give off specific qualities that are reflected in the alcohol's reactivity.

Learn more about triphenylmethanol here:

brainly.com/question/15089315

#SPJ4

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<u>Answer:</u> The mass of decane produced is 1.743\times 10^2g

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To calculate the number of moles, we use the equation:  

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}       ......(1)

Mass of hydrogen gas = 2.45 g

Molar mass of hydrogen gas = 2 g/mol

Putting values in equation 1:, we get:

\text{Moles of }H_2=\frac{2.45g}{2g/mol}=1.225mol

The chemical equation for the hydrogenation of decene follows:

C_{10}H_{20}(l)+H_2(g)\rightarrow C_{10}H_{22}(s)

As, decene is present in excess. So, it is considered as an excess reagent.

Thus, hydrogen gas is a limiting reagent because it limits the formation of products.

By Stoichiometry of the reaction:

1 mole of hydrogen gas produces 1 mole of decane.

So, 1.225 moles of hydrogen gas will produce = \frac{1}{1}\times 1.225=1.225mol of decane

Now, calculating the mass of decane by using equation 1, we get:

Moles of decane = 1.225 mol

Molar mass of decane = 142.30 g/mol

Putting values in equation 1, we get:

1.225mol=\frac{\text{Mass of decane}}{142.30g/mol}\\\\\text{Mass of carbon dioxide}=(1.225mol\times 142.30g/mol)=174.3g=1.743\times 10^2g

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A chemist dissolves 867. mg of pure barium hydroxide in enough water to make up 170. mL of solution. Calculate the pH of the sol
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pH is calculated by taking negative logarithm of hydrogen ion concentration.

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