All categories

3 years ago

Proteins containa. oxygenb. nitrogen c. hydrogen

Chemistry

2 answers:

seraphim [82]3 years ago

7 0

Answer:

All of the above

Explanation:

Proteins contain a long chain of amino acids which are a chain of oxygen, nitrogen, carbon, hydrogen or sulfur.

HOPE THIS HELPED

NeTakaya3 years ago

7 0

Oxygen Nitrogen hydrogen

You might be interested in

There are four substances, A, B C and D. A and C are pure substances. They cannot be broken down into anything simpler by chemic

yarga [219]

The answer is C Becuz D is a compound and that is the only answer that says it

6 0

3 years ago

Which of the following statements is true?

tiny-mole [99]

Statement A is true

8 0

3 years ago

The empirical formula of a compound is CH2O and its molecular weight is 90.09 g/mol. Determine the molecular formula.

Pachacha [2.7K]

Answer : The molecular formula of the compound will be, $C_{3}H_{6}O_3$

Explanation :

Empirical formula : It is the simplest form of the chemical formula which depicts the whole number of atoms of each element present in the compound.

Molecular formula : it is the chemical formula which depicts the actual number of atoms of each element present in the compound.

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

$n=\frac{\text{molecular mass}}{\text{empirical mass}}$

As we are given that the empirical formula of a compound is $CH_2O$ and the molar mass of compound is, 90.09 gram/mol.

The empirical mass of $CH_2O$ = 1(12) + 2(1) + 1(16) = 30 g/eq

$n=\frac{\text{molecular mass}}{\text{empirical mass}}$

$n=\frac{90.09}{30}=3$

Molecular formula = $(CH_2O)_n=(CH_2O)_3=C_{3}H_{6}O_3$

Thus, the molecular formula of the compound will be, $C_{3}H_{6}O_3$

7 0

4 years ago

The enthalpy change for converting 1.00 mol of ice at -25.0 Â°c to water at 70.0 Â°c is __________ kj. the specific heats of ice

Margarita [4]

Answer is: 6,16 kJ.
1) changing temperature of ice from -25°C to 0°C.
Q₁ = m·C·ΔT
Q₁ = 18 g · 2 J/g·°C · 25°C
Q₁ = 900 J.
m(H₂O) = 1mol · 18 g/mol = 18 g.
C - <span>specific heat of ice.
</span>2) changing temperature of water from 0°C to 70°C.
Q₁ = m·C·ΔT
Q₁ = 18 g · 4,18 J/g·°C · 70°C
Q₁ = 5266,8 J.
C - specific heat of water.
Q = Q₁ + Q₂ = 900 J + 5266,8 J
Q = 6166,8 J = 6,16 kJ.

8 0

3 years ago

(Help would be greatly appreciated) What is the molarity of a solution made from 325.4g of AlCl3 with enough water to make 500.0

puteri [66]

Answer:

4.88 M

Explanation:

M = number moles/Volume (L)

MM AlCl3 = 133.34 g/mol

Volume = 500 mL = 0.5 L

number moles = mass/MM = 325.4/133.34 = 2.44 moles AlCl3

M = 2.44/0.5 = 4.88 M

7 0

3 years ago

Proteins containa. oxygenb. nitrogen c. hydrogen​

Proteins containa. oxygenb. nitrogen c. hydrogen