The reaction that would take place if hot tungsten was
surrounded by air is that it would react to the oxygen in air to form non
conducting tungsten oxide and burns out instantly.
<span>8.21 L of C3H8(g)
Lets take c as the molar volume at that temperature.
c L <><> 5c L
C3H8 (g) + 5O2 (g) --> 3CO2 + 4H2O + Q
8.21 L <><> x L
x = (8.21 * 5c)/c = 8.21 * 5 = 41.05 L O2 consumed for a 100% yield.</span>
Answer:
combustion reaction, because the products are CO2 and H2O
Answer:
ΔHrxn = 239 kj/mol
Explanation:
Given data:
Mass of sodium = 0.230 g
Heat produced = 2390 J
Solution:
Chemical equation:
2Na + 2HCl → 2NaCl + H₂
Number of moles of sodium:
Number of moles of sodium = mass / molar mass
Number of moles of sodium = 0.230 g / 23 g/mol
Number of moles of sodium = 0.01 mol
Enthalpy of reaction:
ΔHrxn = 2390 J / 0.01 mol
ΔHrxn = 239000 j/mol
ΔHrxn = 239 kj/mol
Answer : The photon energy of this light in units of nanometers, (nm) is, 
Solution :
Formula used :
where,
E = energy of photon = 
h = Planck's constant = 
c = speed of light = 
= wavelength = ?
Now put all the given values in the above formula, we get:
conversion used : 
Therefore, the photon energy of this light in units of nanometers, (nm) is,
