Answer:
- <u>The container must be built of lead, and it should be kept in a concrete vault.</u>
Explanation:
The goal is to contain the <em>gamma rays</em> to<em> reduce</em> the <em>exposure </em>to their harmful <em>radiation</em>.
The gamma rays are the most energetic electromagnetic radiation: they have the smallest wavelength, the largest frequency, and the largest energy from all the electromagnetic radiations.
Due to that, only very dense substances like lead and concrete can stop the gamma rays. In the case of concrete, large blocks with thick walls are required.
Thus, in a lab the best container for a sample of uranium - 238 that is decaying, emitting gamma rays, must be built of lead, and enclosed in a conrete vault.
Answer:
Classifications according to mandatory, discretionary, or originator controlled policy, or a combination thereof:
a. Mandatory
b. Originator
c. Discretionary
d. Mandatory and Originator combined
Explanation:
a) Mandatory control means that access to the UNIX operating system is restricted.
b) Originator controlled policy implies that the memorandum cannot be distributed without the author's consent or permission.
c) Discretionary means that only certain authorized users, for example, generals, can access the particular room.
d) Combined Mandatory and Originator means that while access is restricted to some people, the originator's consent is still required before access can be granted to the faculty member.
The density of the sample : 0.827 g/L
<h3>Further explanation</h3>
In general, the gas equation can be written
![\large {\boxed {\bold {PV = nRT}}}](https://tex.z-dn.net/?f=%5Clarge%20%7B%5Cboxed%20%7B%5Cbold%20%7BPV%20%3D%20nRT%7D%7D%7D)
where
P = pressure, atm , N/m²
V = volume, liter
n = number of moles
R = gas constant = 0.082 l.atm / mol K (P= atm, v= liter),or 8,314 J/mol K (P=Pa or N/m2, v= m³)
T = temperature, Kelvin
n= 1 mol
MW Neon = 20,1797 g/mol
mass of Neon :
![\tt mass=mol\times MW\\\\mass=1\times 20,1797 =20.1797~g](https://tex.z-dn.net/?f=%5Ctt%20mass%3Dmol%5Ctimes%20MW%5C%5C%5C%5Cmass%3D1%5Ctimes%2020%2C1797%20%3D20.1797~g)
The density of the sample :
![\tt \rho=\dfrac{m}{V}\\\\\rho=\dfrac{20,1797}{24.4}=0.827~g/L](https://tex.z-dn.net/?f=%5Ctt%20%5Crho%3D%5Cdfrac%7Bm%7D%7BV%7D%5C%5C%5C%5C%5Crho%3D%5Cdfrac%7B20%2C1797%7D%7B24.4%7D%3D0.827~g%2FL)
or We can use the ideal gas formula ta find density :
![\tt \rho=\dfrac{P\times MW}{RT}\\\\\rho=\dfrac{1\times 20.1797}{0.082\times 298}\\\\\rho=0.826~g/L](https://tex.z-dn.net/?f=%5Ctt%20%5Crho%3D%5Cdfrac%7BP%5Ctimes%20MW%7D%7BRT%7D%5C%5C%5C%5C%5Crho%3D%5Cdfrac%7B1%5Ctimes%2020.1797%7D%7B0.082%5Ctimes%20298%7D%5C%5C%5C%5C%5Crho%3D0.826~g%2FL)