There are 0.5 moles of NaCl present in a 29.22g sample.
to find moles of a compound you would look at the periodic table to find the mass. in this case, the mass of NaCl is 58.44 g/mol. now, you divide the sample mass of 29.22g by 58.44 g/mol. the grams will cancel each other out and you’re left with 0.5 mol in that sample
hope this helps!
Answer:
Density = 4.06 * 10^14
Explanation:
Givens
r = 1 * 10^-13 cm
m = 1.7 * 10^-24 grams
Formula
V = 4/3 * pi * r^3
D = m/V
Solution
Put the givens into the formula.
V = (4/3) 3.14 * (1 * 10^-13)^3 Find the value for r^3
V = (4/3) 3.14 * 1 * 10^-39 Find the volume. Indicate divide by 3
V = 1.256 10^-38/3
V = 4.1867 * 10^-39
Density = m / v
Density = 1.7*10^-24/4.1867*10^-39 Do the division
Density = .406 * 10^(-24 + 39)
Density = .406 * 10^15 grams/ cm^3
Answer: Density = 4.06 * 10^14
A. 6 moles
B. 9 moles
C. 3 moles
D. 20 moles
I think please check me, in case I am wrong
During a chemical rx a new product is formed
