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3 years ago

Which element is similar to the properties bromine?

Chemistry

1 answer:

Ainat [17]3 years ago

8 0

Answer: Fluorine

Explanation: It belongs in the same group as Bromine

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When molecules are joined I an ordered structure

olga2289 [7]

Answer:

ice

Explanation:

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3 years ago

An 8 oz. bottle of energy drink contains 6.0 g of protein, 2.0 g of fat, and 16.3 g of carbohydrate. The fuel value of this ener

valina [46]

Answer: The correct option is d) 460 kJ

Explanation:

We are given:

Content of fat in energy drink = 2.0 g

Content of protein in energy drink = 6.0 g

Content of carbohydrate in energy drink = 16.3 g

Also,

The fuel value of fat = 38 kJ/g

The fuel value of protein = 17 kJ/g

The fuel value of carbohydrate = 17 kJ/g

So, the fuel value of the energy drink will be:

Total fuel value = $(2.0g\times 38 kJ/g)+(6.0g\times 17 kJ/g)+(16.3g\times 17 kJ/g)$

Total fuel value = $[76+102+277]=460kJ$

Hence, the correct option is d) 460 kJ

4 0

3 years ago

What is the total number of moles of NaCl(s) needed to make 3.0 liters of a 2.0 M NaCl solution? *

RideAnS [48]

Answer:

6 moles of NaCl are needed to make 3.0 liters of a 2.0 M NaCl solution.

Explanation:

A 2M solution means that there are 2 moles of solute (NaCl in this case) in 1 liter of solution:

1 L solution-----2 moles of NaCl

3 L solution----x= (3 L solutionx2 moles of NaCl)/1 L solution= 6 moles of NaCl

5 0

3 years ago

Drop your insta gang’s Let’s be friends

Zanzabum

Why don’t you have friends?

6 0

2 years ago

A compound is found to contain 64.80 % carbon, 13.62 % hydrogen, and 21.58 % oxygen by weight. What is the empirical formula for

insens350 [35]

Answer:

Empirical formula is C₄H₁₀O

Explanation:

Values for C, H and O are determined as centesimal composition.

64.80 g of C in 100g of compound

13.62g of H in 100 g of compound

21.58 g of O in 100 g of compound.

We convert the mass to moles:

64.80 g . 1mol/ 12g = 5.4 moles of C

13.62 g . 1 mol /1g = 13.62 moles of H

21.58 g . 1 mol/16g = 1.35 moles of O

We pick the lowest value and we divide:

5.4 moles of C / 1.35 = 4 C

13.62 moles of H / 1.35 = 10 H

1.35 moles of O / 1.35 = 1 O

Empirical formula is C₄H₁₀O, it can be the diethyl ether.

We confirm, the excersise is well done.

Molar mass = 74g/mol

74 g of compound we have (12 . 4)g of C

In 100 g of compound we may have (100 . 48) / 74 = 64.8 g

5 0

3 years ago