Answer:
0.045 moles
Explanation:
Given data:
Moles of CO = ?
Volume of gas = 1 L
Temperature and pressure = standard
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
n = PV/RT
n = 1 atm× 1L / 0.0821 atm.L/mol.K × 273 K
n = 1 atm.L / 22.41 atm.L/mol
n = 0.045 mol
Answer:
B
Explanation:
You take the 50-69 and you add up the students and it will allow you to get 7
Answer:
The molecular formula is C2H2Br4
Explanation:
Molar Mass of CHBr2 = 12 + 1 + (2x80) = 12 + 1 + 160 = 173
The molecular formula = n x empirical formula
Molar Mass of the compound = 345.6
Empirical formula = CHBr2
n(CHBr2) = 345.6
n x 173 = 345.6
n = 345.6/173 = 2
Therefore the molecular formula is n(CHBr2) = 2(CHBr2) = C2H2Br4
