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otez555 [7]
3 years ago
13

A 1.5m wire carries a 7 A current when a potential difference of 63 V is applied. What is the resistance of the wire? ohms

Physics
1 answer:
zheka24 [161]3 years ago
3 0
To find the resistance, the formula you need to use is
r =  \frac{v}{i}
whereby i reprsents the current and v represents the potential difference.
therefore,
r=63/7
r=9 ohms
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{ \tt{ \frac{1}{v}  +  \frac{1}{u} =  \frac{1}{f}  }} \\

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{ \tt{fv( \frac{1}{v} +  \frac{1}{u} ) = fv( \frac{1}{f}  )}} \\   \\ { \tt{ \frac{fv}{v}  +  \frac{fv}{u}  =  \frac{fv}{f} }} \\  \\  { \tt{f + f( \frac{v}{u} ) = v}}

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