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3 years ago

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A traveler first drives 18.6 km east, then 30.3 km southeast, and finally 10.7 km south. Find the traveler's total displacement

?

1 answer:

NikAS [45]3 years ago

6 0

East: 18.6+30.3/(sqrt2)
South: 19.7+30.3/(sqrt2)
Total displacement: sqrt(east^2+south^2) is 57.3 km

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Answer:

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Explanation:

The momentum of the particle is related to force by the following equation:

Δp = F · Δt

Where:

Δp = change in momentum = final momentum - initial momentum

F = constant force.

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Let´s calculate the x-component of the momentum after the 0.13 s:

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final momentum = -7 kg m/s² · 0.13 s + 8 kg m/s

final momentum = 7.09 kg m/s

Now let´s calculate the y-component of the momentum vector after the 0.13 s. Since the particle wasn´t moving in the y-direction, the initial momentum in this direction is zero:

final momentum = 5 kg m/s² · 0.13 s

final momentum = 0.65 kg m/s

Then, the mometum vector will be as follows:

p = (7.09 kg m/s, 0.65 kg m/s)

The magnitude of this vector is calculated as follows:

$|p| = \sqrt{(7.09 kg m/s)^{2} + (0.65 kg m/s)^{2}} = 7.12 kg m/s$

The momentum of the particle at the end of the 0.13 s time interval is 7.12 kg m/s

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