Ask question

Ask question

All categories

3 years ago

14

A traveler first drives 18.6 km east, then 30.3 km southeast, and finally 10.7 km south. Find the traveler's total displacement

?

1 answer:

NikAS [45]3 years ago

6 0

East: 18.6+30.3/(sqrt2)
South: 19.7+30.3/(sqrt2)
Total displacement: sqrt(east^2+south^2) is 57.3 km

You might be interested in

Suppose a 2.0kg bird is flying at a speed of of 1m/s. It’s kinetic energy would be what?

Ganezh [65]

As we know that the formula of kinetic energy will be

$KE = \frac{1}{2} mv^2$

now here we know that

m = 2 kg

v = 1 m/s

so from the above equation we have

$KE = \frac{1}{2}(2)(1^2)$

$KE = 1 J$

7 0

2 years ago

Uranium 235 can be split if it is hit by:

Lady bird [3.3K]

Your Answer Is: Neutron.

I Hope This Helps !!!!!!

6 0

3 years ago

Which type of electromagnetic radiation has the highest frequency?

Likurg_2 [28]

Explanation:

As we know that relation between energy and wavelength is as follows.

E = $\frac{hc}{\lambda}$

This means that energy is inversely proportional to wavelength. So, more is the energy of an electromagnetic radiation less will be its wavelength.

Also, f = $\frac{c}{\lambda}$

Hence, less will be the wavelength more will frequency of a radiation.

Gamma rays are the rays that have highest energy, small wavelength and highest frequency.

Thus, we can conclude that gamma rays are the electromagnetic radiation which has the highest frequency.

7 0

3 years ago

All objects in the universe are attracted to each other by the force of. A. effort

stepladder [879]

Answer:

It encapsulates the idea that all the particles of matter in the universe attract each other through the force of gravity – Newton's law tells us how strong that attraction is. ...

Explanation:

your answer

4 0

2 years ago

Read 2 more answers

A wheel rotates about a fixed axis with an initial angular velocity of 13 rad/s. During a 8-s interval the angular velocity incr

____ [38]

Answer:

The number of revolutions is 44.6.

Explanation:

We can find the revolutions of the wheel with the following equation:

$\theta = \omega_{0}t + \frac{1}{2}\alpha t^{2}$

Where:

$\omega_{0}$ : is the initial angular velocity = 13 rad/s

t: is the time = 8 s

α: is the angular acceleration

We can find the angular acceleration with the initial and final angular velocities:

$\omega_{f} = \omega_{0} + \alpha t$

Where:

$\omega_{f}$ : is the final angular velocity = 57 rad/s

$\alpha = \frac{\omega_{f} - \omega_{0}}{t} = \frac{57 rad/s - 13 rad/s}{8 s} = 5.5 rad/s^{2}$

Hence, the number of revolutions is:

$\theta = \omega_{0}t + \frac{1}{2}\alpha t^{2} = 13 rad/s*8 s + \frac{1}{2}*5.5 rad/s^{2}*(8 s)^{2} = 280 rad*\frac{1 rev}{2\pi rad} = 44.6 rev$

Therefore, the number of revolutions is 44.6.

I hope it helps you!

4 0

2 years ago