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Sloan [31]
3 years ago
13

A circus performer wants to land in a net 5 meters to the right of where she will let go of the trapeze. If she is 10 meters abo

ve the net, how fast must she be moving horizontally when she lets go? Round your final answer to three significant figures.
Physics
1 answer:
VikaD [51]3 years ago
3 0

Answer:

Assuming no air friction,

the time it takes to fall 10 m = t = √2h/g = √(20/9.8) = 1.43 s

horizontal distance = 5 m

horizontal speed = distance/time = 5/1.43 = 3.5 m/s  ANS

Explanation:

i hope this helps!

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PLEASE HEP FAST PLEASE!!!!! IM SO SCARED!!!! An elevator has the mass of 3 tons of power needed to raise the elevator 50m in 15
gayaneshka [121]

Answer:

Mass=3,height=50 and time=15,g=10,P=?

P=mgh/t....which is 3×10×50=1500/15=100Watts

6 0
3 years ago
Read 2 more answers
As outlaws escape in their getaway ear, which goes 3/4 c, the police officer fires a bullet from a pursuit ear, which only goes
Mariulka [41]

Answer:

a) Bullet will hit

b) Bullets will not hit

Explanation:

Given:

The velocity of the bullet, u = \frac{1}{3}c in the rest frame of the bullet pursuit car

The velocity of the original frame of reference, v = -\frac{1}{2}c with respect to the pursuit car.

Now, according to the Galileo

the velocity of the bullet in the original frame of reference (u') will be

u' = u - v

on substituting the values we get

u' = \frac{1}{3}c-(-\frac{1}{2}c)

or

u' = \frac{1}{3}c+\frac{1}{2}c

or

u' = \frac{5}{6}c

since this velocity ( \frac{5}{6}c) is greater than the ( \frac{3}{4}c)

hence,

<u>the bullet will hit</u>

Now, according to the Einstein theory

the velocity of the bullet in the original frame of reference (u') will be

u'=\frac{u-v}{1-\frac{uv}{c^2}}

on substituting the values we get

u'=\frac{\frac{1}{3}c-\frac{1}{2}c}{1-\frac{\frac{1}{3}c\times \frac{1}{2}c}{c^2}}

or

u'=\frac{\frac{5}{6}c}{1-\frac{1}{6}}

or

u'=\frac{5}{7}c

since,

u'=\frac{5}{7}c is less than  ( \frac{3}{4}c), this means that the bullet will not hit

7 0
3 years ago
if a 60 kg person was standing on a platform at the surface of saturn and they jumped, they would have to push with a force grea
lidiya [134]

Answer:

A 60 kg person standing on a platform at the surface of Saturn and they jumped, they would have to push with a force greater than 540 N

Explanation:

The gravitational attraction between an object on the surface of a planet and the planet is given by the weight of the object

Therefore the force needed to be applied for an object to lift off the surface of a planet = The weight of the object

The weight of the object on the surface of a planet = m × g

Where;

m = The mass of the object

g = The strength of gravity on the planet's surface in N/kg

The given parameters are;

The mass of the person standing on a platform at the surface of Saturn, m = 60 kg

The strength of gravity on the surface of Saturn = 9 N/kg

Therefore, we have;

The weight of the person = The force greater than which the person would have to push on the surface of Saturn so as to Jump = The weight of the person on the surface of Saturn = 60 kg × 9 N/kg = 540 N

Therefore, for a 60 kg person standing on a platform at the surface of Saturn and they jumped, they would have to push with a force greater than 540 N.

4 0
3 years ago
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daser333 [38]

Answer:E none of the above

Explanation:

When a space shuttle orbiting around the earth then earth gravitational force keeps the shuttle in its orbit by providing centripetal force. Tangential velocity makes the shuttle to revolve around the earth. Earth gravitational pull is significant to make the shuttle move in orbit while the Passengers feel weightlessness because they are falling downward but never able to reach as they move fast enough such that earth curves away them.                        

4 0
3 years ago
Please use this screenshot in any way you can
miskamm [114]
Ball 1 Has uchanging motion because it continually goes up no matter what. Ball 2 has no motion. And ball 3 changing motion because it goes from not moving to moving. Hope this helps
7 0
3 years ago
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