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Sloan [31]
3 years ago
13

A circus performer wants to land in a net 5 meters to the right of where she will let go of the trapeze. If she is 10 meters abo

ve the net, how fast must she be moving horizontally when she lets go? Round your final answer to three significant figures.
Physics
1 answer:
VikaD [51]3 years ago
3 0

Answer:

Assuming no air friction,

the time it takes to fall 10 m = t = √2h/g = √(20/9.8) = 1.43 s

horizontal distance = 5 m

horizontal speed = distance/time = 5/1.43 = 3.5 m/s  ANS

Explanation:

i hope this helps!

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Answer:

Distance travelled is 7 meters and the displacement is 3 meters

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3 years ago
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If an object undergoes a change in momentum of 10 kg m/s in 3 s ,then the force acting on it is
Paha777 [63]

Answer:

Force = 3.333 Newton

Explanation:

Given the following data;

Change in momentum = 10 Kgm/s

Time = 3 seconds

To find the force acting on it;

In Physics, the change in momentum of a physical object is equal to the impulse experienced by the physical object.

Mathematically, it is given by the formula;

Force * time = mass * change in velocity

Impulse = force * time

Substituting into the formula, we have;

10 = force * 3

Force = 10/3

Force = 3.333 Newton

8 0
3 years ago
The midpoint M of a guitar string is pulled a distance d = 1.7 mm from equilibrium and released. Point M is observed to undergo
nlexa [21]

Answer:

ω = 380π rad/s

Explanation:

The formula for the angular frequency is the oscillation frequency f (hertz) multiplied by 2π

ω = 2πf

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8 0
2 years ago
A baseball has mass 0.147 kg. If the velocity of a pitched ball has a magnitude of 44.5 m/s and the batted ball's velocity is 55
Anit [1.1K]

Explanation:

We have,

Mass of a baseball is 0.147 kg

Initial velocity of the baseball is 44.5 m/s

The ball is moved in the opposite direction with a velocity of 55.5 m/s

It is required to find the magnitude of the change in momentum of the ball and of the impulse applied to it by the bat.

Change in momentum,

\Delta p=mv-mu\\\\\Delta p=m(v-u)\\\\\Delta p=0.147\times ((-55.5)-44.5)\\\\\Delta p=-14.7\ kg-m/s\\\\|\Delta p|=14.7\ kg-m/s

Impulse = 14.7 kg-m/s

Therefore, the magnitude of the change in momentum of the ball and of the impulse applied to it by the bat is 14.7 kg-m/s

4 0
3 years ago
Why might this cloud formation be termed the “Pillars of Creation"?
Oduvanchick [21]

Answer:

I think the answer might be A

Explanation:

because if its called Pillars creation then something important might be being born maybe

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