A circus performer wants to land in a net 5 meters to the right of where she will let go of the trapeze. If she is 10 meters abo
ve the net, how fast must she be moving horizontally when she lets go? Round your final answer to three significant figures.
1 answer:
Answer:
Assuming no air friction,
the time it takes to fall 10 m = t = √2h/g = √(20/9.8) = 1.43 s
horizontal distance = 5 m
horizontal speed = distance/time = 5/1.43 = 3.5 m/s ANS
Explanation:
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