Answer:
0.41kg/sec
Explanation:
PV= nRT
Given : V= 505 L
P=0.88 atm
R= 0.08206 Latm/K*mol
T= 172 .0C = 172+273 = 445 K
n = PV /RT = 0.88 * 505 / 0.08206 * 445 = 12.17 moles per sec of N2 are consumed
As per reaction : N2 + 3H2 ----> 2NH3
1 mole N2 is consumed to produce 2 moles NH3
moles of NH3 produced per sec :
(2 moles NH3/1mol N2) * 12.17 moles N2 = 24.34 moles NH3 per sec
grams of NH3 produced per sec =
24.34 moles NH3 per sec * molar mass NH3 = 24.34 moles NH3 per sec * 17.031 g/mol = 414.5 g NH3 per sec
rate in Kg/sec = 414.5 g NH3 per sec * (1kg /1000g) = 0.4145 Kg/sec
= 0.41kg/sec
Answer:
The electrophile is the hydroxide free radical
Explanation:
The hydroxylation of benzene and benzene derivatives using hydrogen peroxide proceeds in the presence of an acidic catalyst. The electrophile in this reaction is the hydroxyl free radical generated in an initial step of the reaction.
This is actually a free radical reaction. The hydroxyl radical previously generated reacts with the benzene ring to yield a radical that undergoes further rearrangement to yield the product phenol. The intermediate, shown as part of this reaction mechanism (refer to image attached) is a specie in which the odd electron is delocalized over the entire benzene ring. Loss of a proton completes the reaction mechanism yielding the corresponding phenol.
Answer:
(A). C6H5Br + Mg(in ether) -----------> C6H5MgBr.
(B). C6H5MgBr + O = C = O -----------> C6H5-COO^- Mg^+ Br.
(C). C6H5-COO^- Mg^+ Br + HCl --------> C6H5-COOH + Mg^+Br(OH).
PRODUCTS=> C6H5-COOH and Mg^+Br(OH).
Explanation:
A Grignard reagent is a reagent that/which is an organometallic compound that is R -Mg- X. The R = alkyl, vinyl or allyl and the X = halogens.
It must be noted that an important reaction of Grignard reagent is its reaction with compounds containing the Carbonyl that is -CO functional group and this kind of Reaction is known as a Grignard Reaction.
So, in this question we are told that;
=> "1-bromo-benzene andits subsequent reaction with solid carbon dioxide (CO2) followed by acidic workup (using HCl asthe acid). "
Thus;
(A). C6H5Br + Mg(in ether) -----------> C6H5MgBr.
(B). C6H5MgBr + O = C = O -----------> C6H5-COO^- Mg^+ Br.
(C). C6H5-COO^- Mg^+ Br + HCl --------> C6H5-COOH + Mg^+Br(OH).
Elements that have different atomic mass
<span>Dalton's atomic theory originally has 5 postulates. Among the choices, there are three that are included. These are:
*atoms of one element cannot change into atoms of another element.
</span><span>*each element is composed of tiny, indestructible particles called atoms.
</span><span>*atoms combine in simple, whole number ratios to form compounds
The others are incorrect. Atoms of one element cannot change to another element. Atoms of the same element do not have the same mass because they can occur as isotopes. Nuclear particles are not part of Dalton's theory, just the chemical reactions.</span>
