What is the molar solubility in water of ag2cro4 ? (the ksp for ag2cro4 is 8 x 10-12. )
2 answers:
The molar solubility in water of Ag₂CrO₄ is 2.52 * 10⁻⁴ M .
<h3>How do you define Solubility ?</h3>
The measure of the degree to which a substance gets dissolved in a solvent to become a solution.
The formula for determination of molar solubity is
= solubility product constant
= cation in an aqueous solution
= anion in an aqueous solution
a, b = relative concentrations of a and b
We have the data given as
for Ag₂CrO₄ is 8 x 10⁻¹²
For Silver chromate , the solubility would be only one-half of the Ag⁺ concentration.
We denote the solubility of Ag₂CrO₄ as S mol L⁻¹.
Then for a saturated solution, we have
[Ag⁺]=2S
[CrO₂⁴⁻]=S
the relation between the solubility and the solubility product constant depends on the stoichiometry of the dissolution reaction
(2S)²(S)=4S³ = 8 * 10⁻¹²
S=∛ (2*10⁻¹²)
S= 1.26 * 10⁻⁴ M
2S = 2.52 * 10⁻⁴ M
Therefore the molar solubility in water of Ag₂CrO₄ is 2.52 * 10⁻⁴ M .
To know more about Solubility
#SPJ4
You might be interested in
Answer:- 71.7 calories
Solution:- it is a unit conversion problem where we need to convert joules into calories.
The unit conversion for these energy units is:
1 calorie = 4.184 joule
The given energy is 300 joules and has to be converted to calories. We will show the set up using dimensional analysis.
= 71.7 calories
So, the energy in calories is 71.7.