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Fynjy0 [20]
2 years ago
10

What is the molar solubility in water of ag2cro4 ? (the ksp for ag2cro4 is 8 x 10-12. )

Chemistry
2 answers:
nikitadnepr [17]2 years ago
4 0

The molar solubility in water of Ag₂CrO₄ is 2.52 * 10⁻⁴ M .

<h3>How do you define Solubility ?</h3>

The measure of the degree to which a substance gets dissolved in a solvent to become a solution.

The formula for determination of molar solubity is

\rm K_{sp} =  [A^+]^a [B^-]^b

\rm K_{sp}          = solubility product constant

\rm [A^+]^a  =     cation in an aqueous solution

\rm  [B^-]^b  = anion in an aqueous solution

a, b          = relative concentrations of a and b

We have the data given as

\rm K_{sp} for Ag₂CrO₄ is 8 x 10⁻¹²

For Silver chromate , the solubility would be only one-half of the Ag⁺ concentration.

We denote the solubility of Ag₂CrO₄ as S mol L⁻¹.

Then for a saturated solution, we have

[Ag⁺]=2S

[CrO₂⁴⁻]=S

the relation between the solubility and the solubility product constant depends on the stoichiometry of the dissolution reaction

(2S)²(S)=4S³ = 8 * 10⁻¹²

S=∛ (2*10⁻¹²)

S= 1.26 * 10⁻⁴ M

2S = 2.52 * 10⁻⁴ M

Therefore the molar solubility in water of Ag₂CrO₄ is 2.52 * 10⁻⁴ M .

To know more about Solubility

brainly.com/question/8591226

#SPJ4

qaws [65]2 years ago
3 0

Answer:

¿Cuál será el pH de una disolución saturada de hidróxido de cinc?.

Explanation:

Dato: Kps (Zn(OH)2) = 1,8 x 10-14. Solución: 9,52.

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A 0.1 gram sample of an unknown liquid is vaporized completely at 70 degrees C to fill a 750mL flask. The pressure is 0.05951atm
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Answer:

The molar mass of the liquid 62.89 g/mol

Explanation:

Step 1: Data given

Mass of the sample = 0.1 grams

Temperature = 70°C

Volume = 750 mL

Pressure = 0.05951 atm

Step 2: Calculate the number of moles

p*V = n*R*T

n = (p*V)/(R*T)

⇒ with n = the number of moles gas = TO BE DETERMINED

⇒ with p = The pressure = 0.05951 atm

⇒ with V = The volume of the flask = 750 mL = 0.750 L

⇒ with R = The gasconstant = 0.08206 L*atm/K*mol

⇒with T = the temperature = 70 °C = 343 Kelvin

n = (0.05951 *0.750)/(0.08206*343)

n = 0.00159 moles

Step 3: Calculate molar mass

Molar mass = mass / moles

Molar mass =0.1 gram /  0.00159 moles

Molar mass = 62.89 g/mol

The molar mass of the liquid 62.89 g/mol

6 0
3 years ago
Pls help and show work!!!
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Answer:

44.9g

Explanation:

You have to convert grams of CH4 to moles, use the mole-to-mole ratio of CH4 to water, and convert back to grams.

(20.0g CH4)(1 mol CH4/16.04g)(2 mol H2O/1 mol CH4)(18.01 g H2O/ 1 mol) = 44.9127 g

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