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densk [106]
3 years ago
5

What is the volume in liters of 321 g of a liquid with a density of 0.84 g/mL?

Chemistry
2 answers:
garri49 [273]3 years ago
7 0
If we have 321 grams of a liquid, and the density is 0.84 g/mL, then we can easily find the volume of the liquid. We just need to take this 0.84 and multiply that by the number of grams. If we do 321 * 0.84, we get 269.64 mL. This is the volume that this liquid has.Remember this equation for future problems: V = D*M. V meaning volume, D meaning density, and M meaning mass. I hope this helps.
Katena32 [7]3 years ago
5 0

<u>Answer:</u> The volume of liquid is 0.382 L

<u>Explanation:</u>

Density of a substance is defined as the ratio of its mass and volume. The equation used to determine density follows:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

We are given:

Density of liquid = 0.84 g/mL

Mass of liquid = 321 g

Putting values in above equation, we get:

0.84g/mL=\frac{321g}{\text{Volume of liquid}}\\\\\text{Volume of liquid}=\frac{321g}{0.84g/mL}=382.1mL

Converting this into liters, we use the conversion factor:

1 L = 1000 mL

So, 382.1mL\times \frac{1L}{1000mL}=0.382L

Hence, the volume of liquid is 0.382 L

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<h3>what is Krebs cycle ?</h3>

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1 year ago
4.1 moles of sodium carbonate to molecules of sodium carbonate.​
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<h3>Answer:</h3>

2.47 × 10^24 molecules

<h3>Explanation:</h3>

One mole of a compound contains molecules equivalent to the Avogadro's number, 6.022 × 10^23.

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1 mole of Na₂CO₃ = 6.022 × 10^23 molecules

Thus, we can calculate the number of molecules in 4.1 moles of Na₂CO₃

we get,

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