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3 years ago

What is the volume in liters of 321 g of a liquid with a density of 0.84 g/mL?

2 answers:

7 0

If we have 321 grams of a liquid, and the density is 0.84 g/mL, then we can easily find the volume of the liquid. We just need to take this 0.84 and multiply that by the number of grams. If we do 321 * 0.84, we get 269.64 mL. This is the volume that this liquid has.Remember this equation for future problems: V = D*M. V meaning volume, D meaning density, and M meaning mass. I hope this helps.

Katena32 [7]3 years ago

5 0

<u>Answer:</u> The volume of liquid is 0.382 L

<u>Explanation:</u>

Density of a substance is defined as the ratio of its mass and volume. The equation used to determine density follows:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

We are given:

Density of liquid = 0.84 g/mL

Mass of liquid = 321 g

Putting values in above equation, we get:

$0.84g/mL=\frac{321g}{\text{Volume of liquid}}\\\\\text{Volume of liquid}=\frac{321g}{0.84g/mL}=382.1mL$

Converting this into liters, we use the conversion factor:

1 L = 1000 mL

So, $382.1mL\times \frac{1L}{1000mL}=0.382L$

Hence, the volume of liquid is 0.382 L

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Answer:

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1. Calculate the concentration of hydronium ion of both buffer solutions at their starting pHs. Calculate the moles of hydronium ion present in 20.0 mL of each buffer.

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Actual ph of the buffer 5.27

volume of the buffer used in buffer capacity titration 20.0 mL

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