1 mole ------------- 6.02 x 10²³ atoms
0.70 moles -------- ( atoms platinum )
atoms platinum = 0.70 x ( 6.02 x 10²³ ) / 1
= 4.2 x 10²³ atoms platinum
hope this helps!
Meteorologists also use satellites to observe cloud patterns around the world, and radar is used to measure precipitation. All of this data is then plugged into super computers, which use numerical forecast equations to create forecast models of the atmosphere.
Answer:
10.4664 grams of CO
Explanation:
Remark
There's a couple of things you must look out for in this question.
1. The use of the term atoms. There are 2 atoms in each mol of CO
2. You need to divide by 2 to find the number of molecules which will lead to moles.
<u>Step one</u>
Divide the number of atoms by 2
4.50 e^23 / 2 atoms = 2.25 * 10^23 molecules.
<u>Step Two</u>
Find the number of moles of CO
1 mol of anything is 6.02 * 10^23 molecules in this case
x = 2.25 * 10^23 molecules
1/x = 6.02 * 10^23/2.25 * 10 ^23 Cross multiply
1 * 2.25 * 10^23 = 6.02*10^23 * x Divide by 6.02 * 10^23
2.25 * 10 ^ 23 / 6.02 * 10^23 = x
x = .3738 moles of CO
<u>Step Three</u>
Find the gram molecular mass of CO
C = 12
O = 16
1 mole = 12 + 16 = 28 grams.
<u>Step Four</u>
Find the number of gram in 0.3738 mols
1 mol = 28 grams
0.3738 mol = x Cross multiply
x = 28 * 0.3738
x = 10.4664 grams
Answer:
C. product costs and expensed when the goods are sold
Explanation:
Mass of Oxygen : 18.8 g
<h3>Further explanation</h3>
Reaction(balanced) :
4Fe + 3O₂ → 2Fe₂O₃
mass Fe = 43.7 g
mol Fe(MW= 55,845 g/mol) :
mol O₂ : mol Fe = 3 : 4, so mol O₂ :
Mass O₂(MW=32 g/mol) :
Or simply you can Conservation of mass, where the masses before and after the reaction are the same
<em>mass reactants=mass products</em>
mass iron+mass oxygen=mass iron (III) oxide
43.7 g + mass oxygen=62.5 g
mass oxygen = 62.5 - 43.7 = 18.8 g
