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VashaNatasha [74]
2 years ago
8

If you have 20 grams of carbon-14 and it goes through 2 half lives, how much carbon-14 is left?

Chemistry
1 answer:
Pie2 years ago
8 0

Answer: I belive it is 25%. Correct me if you know the answer or think I am wrong.

Explanation:

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You add 4.7 gg iron to 27.10 mL of water and observe that the volume of iron and water together is 27.70 mLmL . Calculate the de
sattari [20]

Answer : The density of iron is, 7.8 g/mL

Explanation : Given,

Mass of iron = 4.7 g

Volume of water = 27.10 mL

Volume of water and iron = 27.70 mL

First we have to calculate the volume of iron.

Volume of iron = Volume of water and iron - Volume of water

Volume of iron = 27.70 mL - 27.10 mL

Volume of iron = 0.6 mL

Now we have to calculate the density of iron.

\text{Density of iron}=\frac{\text{Mass of iron}}{\text{Volume of iron}}

Now put all the given values in this expression, we get:

\text{Density of iron}=\frac{4.7g}{0.6mL}

\text{Density of iron}=7.8g/mL

Thus, the density of iron is, 7.8 g/mL

5 0
3 years ago
Sodium hydroxide (NaOH) and hydrochloric acid (HCl) react to form sodium chloride (NaCl) and water according to the equation:
Phantasy [73]
<span>NaOH + HCl → NaCl + H2O
1 mol                             1 mol
</span>2.75 × 10⁻⁴ mol              2.75 × 10⁻⁴ mol

M(H2O) = 2*1.0 +16.0 = 18.0 g/mol

2.75 × 10⁻⁴ mol H2O * 18.0 g H2O/1 mol H2O = 4.95*10⁻³ g H2O
3 0
3 years ago
Read 2 more answers
If you start with 512 grams of aluminum and 1147 grams of copper chloride to make aluminum chloride and copper, what is the limi
Setler [38]

Answer:

Copper (II) chloride.

Explanation:

Hello,

In this case, considering the described reaction which is also given as:

2Al + 3CuCl_2 \rightarrow 2AlCl_3 + 3Cu

For us to identify the limiting reactant we first compute the available moles of aluminium:

n_{Al}=512gAl*\frac{1molAl}{27gAl}=19.0molAl

Next, we compute the consumed moles of aluminium by the 1147 grams of copper (II) chloride by using their 2:3 molar ratio:

n_{Al}^{consumed}=1147gCuCl_2*\frac{1molCuCl_2}{134.45gCuCl_2}*\frac{2molAl}{3molCuCl_2}  =5.69molAl

Thereby, we can infer aluminium is in excess since less moles are consumed than available whereas the copper (II) chloride is the limiting reactant.

Best regards.

5 0
3 years ago
Which of the following elements belong to the same pair?
butalik [34]

Answer:

B. Na and Li

Both are group I elements.

5 0
3 years ago
The smallest units of matter that normally CANNOT be broken down are atoms. molecules. cells. phospholipids.
olya-2409 [2.1K]

Answer: atoms

Explanation:

All matter is made up of smaller indivisible particles called atoms. These atoms are the smallest units of matter ACCORDING to the Dalton's Atomic theory.

Molecules are combined atoms, while cells and phospholipids are complex combination of atoms.

Therefore, atoms is the answer

4 0
4 years ago
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