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Lunna [17]
2 years ago
11

If you start with 512 grams of aluminum and 1147 grams of copper chloride to make aluminum chloride and copper, what is the limi

ting reagent? 2Al + 3CuCl -> 2AlCl3 + 3Cu
Chemistry
1 answer:
Setler [38]2 years ago
5 0

Answer:

Copper (II) chloride.

Explanation:

Hello,

In this case, considering the described reaction which is also given as:

2Al + 3CuCl_2 \rightarrow 2AlCl_3 + 3Cu

For us to identify the limiting reactant we first compute the available moles of aluminium:

n_{Al}=512gAl*\frac{1molAl}{27gAl}=19.0molAl

Next, we compute the consumed moles of aluminium by the 1147 grams of copper (II) chloride by using their 2:3 molar ratio:

n_{Al}^{consumed}=1147gCuCl_2*\frac{1molCuCl_2}{134.45gCuCl_2}*\frac{2molAl}{3molCuCl_2}  =5.69molAl

Thereby, we can infer aluminium is in excess since less moles are consumed than available whereas the copper (II) chloride is the limiting reactant.

Best regards.

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Virty [35]
 <span>To find the molar mass, look at a periodic table for each element. 
Ibuprofen, C13 H18 and O2. Carbon has a molar mass of 12.01 g, Hydrogen has 1.008 g per mole, and Oxygen is 16.00 g per mole. 

C: 13 * 12.01 
H: 18 * 1.008 
O: 2 * 16.00 
Calculate that, add them all together, and that is the molar mass of C13H18O2. 
Molar mass: 206.274 

Next, you have 200mg in each tablet, with a ratio of C13H18O2 (molar mass) in GRAMS per Mole 
So, you need to convert miligrams into grams, which is 200 divided by 1000. 
0.2 g / Unknown mole = 206.274 g / 1 Mole 

This is a cross multiplying ratio where you're going to solve for the unknown moles of grams per tablet compared to the moles per ibuprofen. 
So, it's set up as: 
0.2 g * 1 mole = 206.274 * x 
0.2 = 206.274x 
divide each side by 206.274 to get X alone 
X = 0.00097 
or 9.7 * 10^-4 moles 

The last problem should be easy to figure out now that you have the numbers. 1 dose is 2 tablets, which is the moles we just calculated above, times four for the dosage. 
</span>
5 0
2 years ago
Read 2 more answers
Sierra did 500 J of work to move her couch. If she exerts 250 N of force on the couch, How fat did she move it? (Work: W = Fd
Elodia [21]
W=F*d

W= 500 J
F = 250 N

500 J = 250 N * d
d= 500J/250 N = 2 J/N = 2(N*m)/N = 2 m
Answer is 2 m.
7 0
3 years ago
One tank of gold fish is fed the normal amount of food once a day. A second tank is fed twice a day. A third tank is fed four ti
Arturiano [62]

The question is incomplete, the complete question is;

One tank of goldfish is feed the normal amount which is once a day, a second tank is fed twice a day, and a third tank is fed four times a day during a 6 week study. The fishes' body fat is recorded daily.

Independent Variable-

Dependent Variable-

Constants

Control Group-

Answer:

A) The amount of food the gold fish receives

B) Body fat of the gold fish

C) -Type of fish used in the study (gold fish)

Time period within which the fishes were fed (Six week period)

Shape and size of tank

D) group of gold fish fed the normal amount

Explanation:

The purpose of the study is to determined the impact of amount of feed on the body fat of gold fish. Hence, the amount of feed is the independent variable while the body fat of the feed is the dependent variable.

The control group receives the normal amount of feed (once a day). The fishes are all gold fish, fed within a six week period. All the tanks were of the same shape and size. These are the constants in the study.

4 0
2 years ago
What is true of a compound? . a. It does not retain the properties of the substances that make it up. b. It retains the properti
LekaFEV [45]
A. It does not retain the properties of the substances that make it up
8 0
3 years ago
Archeologists can determine the age of artifacts made of wood or bone by measuring the amount of the radioactive isotope 14C pre
Ahat [919]

Answer: The age of the tool is 15539 years

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  

t = age of sample

a = let initial amount of the reactant = 100

a - x = amount left after decay process = \frac{15.5}{100}\times 100=15.5  

a) for completion of half life:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.  

t_{\frac{1}{2}}=\frac{0.693}{k}

k=\frac{0.693}{5730yr}=0.00012yr^{-1}

b) for 15.5 % of original amount

t=\frac{2.303}{0.00012}\log\frac{100}{15.5}

t=15539years

Thus age of the tool is 15539 years

8 0
2 years ago
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