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pochemuha
2 years ago
13

What is the graphed version of f(x)= 5cos ?

Mathematics
1 answer:
nata0808 [166]2 years ago
7 0

Step-by-step explanation:

it follows the same structure on the x-axis as cosine, but the curve is stretched up an down to reach values between -5 and +5 instead of between -1 and +1

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I need some help please
ExtremeBDS [4]
Using the law of cosins

sin(angle) = Opposite Leg / Hypotenuse

The angle is given as 35 degree and the hypotenuse is given as 30 feet.

Sin(35) = X ( opposite leg) / 30

X = 30 * sin(35)

x = 17.2 feet.

Total height = 17.2 + 6.5 = 23.7, round to 24 feet.

The answer is 24 feet.
6 0
3 years ago
First consider 100% what is the 100% of 40
suter [353]

Answer:

Step-by-step explanation:

100% means all of 40.

So 100% of 40 is 40

4 0
3 years ago
Read 2 more answers
A cube has a surface area of 486 cm2. What is the side length ?
astraxan [27]
A Cube, has all equal sides, namely, the length, width and height
are all equal to each other

so..  notice the picture added here
you have really, 6 squares, stacked up to each other at the edges

so...what is the Area of one of those squares?
well, if the sides are equal, let's say the side is "x" long, then
the Area is x\cdot x \implies x^2

well, you have 6 of those squares, thus \bf \textit{surface area of a cube}=
\begin{cases}
(x\cdot x)+\\
(x\cdot x)+\\
(x\cdot x)+\\
(x\cdot x)+\\
(x\cdot x)+\\
(x\cdot x)\\
 --------------\\
 x^2+x^2+x^2+x^2+x^2\\
6x^2
\end{cases}
\\\\
\textit{we know the Area is }486\ cm^2\qquad thus
\\\\
\textit{surface area}=6x^2\implies 486=6x^2

solve for "x", to get one side's length

3 0
3 years ago
X^2-14x-4=0, solve by completing the square
REY [17]
The answer is: x = 7 - √53      or      x = 7 + √53

The general quadratic equation is: ax² + bx + c  = 0.
But, by completing the square we turn it into: a(x + d)² + e = 0, where:<span>
d = b/2a
e = c - b²/4a
Our quadratic equation is x² - 14x -4 = 0, which is after rearrangement:
So, a = 1, b = -14, c = -4
Let's first calculate d and e:
d = b/2a = -14/2*1 = -14/2 = -7
e = c - b²/4a = -4 - (-14)</span>²/4*1 = -4 - 196/4 = -4 - 49 = -53<span>
By completing the square we have:
a(x + d)² + e = 0

1(x + (-7))</span>² + (-53) = 0
(x - 7)² - 53 = 0
(x - 7)² = 53
x - 7 = +/-√53
x = 7 +/- √53

Therefore, the solutions are:
x = 7 - √53
or
x = 7 + √53
4 0
3 years ago
Read 2 more answers
How can you tell if the slope of a tangent line belongs to a certain interval?
Mila [183]

The slope of the function is given by its derivative. You want to find the values of x such that the derivative is between -1 and 1.

... f'(x) = 0.4x +5

... -1 < 0.4x +5 < 1 . . . . . your requirement for slope

... -6 < 0.4x < -4 . . . . . . subtract 5

... -15 < x < -10 . . . . . . . multiply by 2.5


Any value of x that is between -15 and -10 will be one where the tangent line has a slope between -1 and 1.


_____

The graph shows tangent lines with slopes of -1 and +1. You can see that the slope of the graph of f(x) is between those values when x is between the tangent points.

5 0
3 years ago
Read 2 more answers
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