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snow_tiger [21]
2 years ago
6

What does the word "atom"

Physics
2 answers:
lawyer [7]2 years ago
8 0

Answer: A tiny particle

Explanation:

Atoms are the smallest that make up all living matter

Oliga [24]2 years ago
7 0

Answer:

in greek atom means uncuttable

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The portion of electromagnetic spectrum is occupied by signal is called ​
Alex Ar [27]

Answer:

the portion of electromagnetic spectrum is occupied by signal is called ​bandwidth

Explanation:

Bandwidth is the part of electromagnetic spectrum which is occupied by the signal. It is also called as the range  of frequency over which the receiver or any other electronic circuit works. Bandwidth is the amount of the data been transmitted  from one point to other within the network in the specific amount of the time. It is expressed as the bit rate and are measured as bits per seconds (bps). Bandwidth is the sum of the connections.

3 0
3 years ago
Two curves on a highway have the same radii. However, one is unbanked and the other is banked at an angle θ. A car can safely tr
Leviafan [203]

Answer:

θ = 29.38°

Explanation:

The centripetal force is given by the formula;

F_c = F_n(sin θ) = mv²/r

Now, the vertical component of the normal force is; F_n(cos θ)

Now, this vertical component is also expressed as; F_n(cos θ) = mg

Thus, the slope is;

F_n(sin θ)/F_n(cos θ) = (mv²/r)/mg

tan θ = v²/rg

v² = rg(tan θ)

The initial speed will be gotten from the relation;

(v_o)² = μ_s(gr)

Plugging rg(tan θ) for (v_o)², we have;

μ_s(gr) = rg(tan θ)

rg will cancel out to give;

μ_s = (tan θ)

Thus, θ = tan^(-1) μ_s

μ_s is coefficient of static friction given as 0.563

θ = tan^(-1) 0.563

θ = 29.38°

7 0
3 years ago
A 1 kg flashlight is dropped from rest and falls to the floor without air resistance . At the point during its fall, when it is
alexgriva [62]

Answer:

The speed of the flashlight at that point is 3.7 m/s

Explanation:

When an object of mass M is at a height H above the ground, the potential energy of the object is:

U = M*H*g

Where g is the gravitational acceleration, g = 9.8 m/s^2

And for an object with velocity v, the kinetic energy is:

K = (M/2)*v^2

We know that when the flashlight of mass  1kg is 0.7 meters above the ground, the potential energy is equal to the kinetic energy, then:

M = 1kg

H = 0.7m

g = 9.8 m/s^2

Replacing these in the equations, we get:

U = K

(1kg)*(0.7m)*(9.8 m/s^2) = ((1kg)/2)*v^2

As the mass factor appears in both sides, we can remove it:

(0.7 m)*(9.8 m/s^2) = (v^2)/2

Now we can multiply both sides by 2:

2*(0.7 m)*(9.8 m/s^2) = v^2

Now let's apply the square root to both sides:

√(2*(0.7 m)*(9.8 m/s^2)) = v = 3.7 m/s

8 0
3 years ago
When light of wavelength 160 nm falls on a gold surface, electrons having a maximum kinetic energy of 2. 66 ev are emitted. Find
enyata [817]

When the light of wavelength is falling on gold surface, the electrons begin to exchange energies.

a)The work function in eV is Φ =5.097 eV.

b) The cut-off wavelength is λ₀ = 243.71 nm

c) The frequency is ν₀  =1.231 × 10¹⁵ Hz

<h3>What is work function?</h3>

The energy needed for a particle to escape and break through the surface.

The kinetic energy of the light emitted is 2.66 eV and wavelength of the light is 160 nm = 160 × 10⁻⁹ m.

a) The work function of the gold for given maximum kinetic energy is

Φ = hc / λ  - K.Emax

Substituting 6.626 × 10⁻³⁴ J.s for h, 3 × 10⁸ m/s for c and 2.66 eV for K.Emax, work function will be

Φ =8.16 × 10⁻¹⁹ J

1 eV = 1.6 × 10⁻¹⁹

The work function in eV is Φ =5.097 eV.

b) The cutoff wavelength is related to work function as

λ₀ = hc / Φ

Substitute the corresponding values into the equation, we get the cut off wavelength

λ₀ = 243.71 nm

c) The frequency corresponding to the cut-off wavelength is

ν₀ = c / λ₀

Substitute the corresponding values into the equation, we get the frequency,

ν₀  =1.231 × 10¹⁵ Hz

Therefore, the values for the following are

a)The work function in eV is Φ =5.097 eV.

b) The cut-off wavelength is λ₀ = 243.71 nm

c) The frequency is ν₀  =1.231 × 10¹⁵ Hz

Learn more about wave function.

brainly.com/question/17484291

#SPJ4

3 0
2 years ago
To drive a car at a constant velocity, you
kipiarov [429]

Answer:

the answer is C

Explanation:

The car, first is at rest and if you don't accelerate it won't move. When to hit the gas it will accelerate from rest

8 0
2 years ago
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