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Lesechka [4]
3 years ago
11

A scientist told his student assistants that he had sorted groups of mice by their intelligence and asked the assistants to asse

ss the groups’ maze-solving abilities. The scientist had not actually sorted the mice by intelligence. The students rated the “highest intelligence” group of mice as the best maze solvers and the “lowest intelligence” group as the worst maze solvers. What was the scientist trying to demonstrate by doing this experiment?
Experimental subjects should never be put into groups.
Mice should not be judged by their intelligence.
Higher intelligence mice are better maze solvers.
People can introduce their own biases into an experiment.
Physics
2 answers:
Yanka [14]3 years ago
6 0

Answer:

d

Explanation:

VikaD [51]3 years ago
3 0
The right answer for the question that is being asked and shown above is that: "People can introduce their own biases into an experiment."  the scientist trying to demonstrate by doing this experiment is that People can introduce their own biases into an experiment.<span>
</span>
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At the local hockey rink, a puck with a mass of 0.12kg is given an initial speed of 5.3m/s. If the coefficient of friction betwe
Salsk061 [2.6K]
Here’s my work to your question. I used Newton’s Second Law and a kinematics equation to arrive at the answer.

5 0
2 years ago
Help me calculate the kinetic energy (just the middle column) ASAP! SHOW WORK! ON PAPER
lukranit [14]

Answer:

Explanation:

I can tell you what the answers for the middle column are, but if you don't know how to solve total energy problems, they won't make any sense to you at all.

First row, KE = 0

Second row, KE = 220500 J

Third row, KE = 183750 J

Fourth row, KE = 205800 J

That's also not paying any attention to significant digits because your velocity only had 1 and that's not enough to do the problem justice. I left all the digits in the answer. Round how your teacher tells you to.

3 0
3 years ago
Una locomotiva traina un solo vagone, che ha la sua stessa massa, con la forza di
gregori [183]

Answer:

c)    F = 16000 N

Explanation:

For this exercise we use Newton's second law

         F = ma

they tell us that adding the other wagons the acceleration of the locomotive must be maintained

 

      F = m a

by adding the other four wagons

mass = 4 no

therefore to maintain the force you must also raise the same factor

         Fe = 4Fo

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3 0
3 years ago
A 14,700 N car is traveling at 25 m/s. The brakes are applied suddenly, and the car slides to a stop. The average braking force
Vlada [557]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

vo = 25 m/sec 
<span>vf = 0 m/sec </span>
<span>Fμ = 7100 N (Force due to friction) </span>
<span>Fg = 14700 N </span>
<span>With the force due to gravity, you can find the mass of the car: </span>
<span>F = ma </span>
<span>14700 N = m (9.8 m/sec²) </span>
<span>m = 1500 kg </span>
<span>Now, we can use the equation again to find the deacceleration due to friction: </span>
<span>F = ma </span>
<span>7100 N = (1500 kg) a </span>
<span>a = 4.73333333333 m/sec² </span>
<span>And now, we can use a velocity formula to find the distance traveled: </span>
<span>vf² = vo² + 2a∆d </span>
<span>0 = (25 m/sec)² + 2 (-4.73333333333 m/sec²) ∆d </span>
<span>0 = 625 m²/sec² + (-9.466666666667 m/sec²) ∆d </span>
<span>-625 m²/sec² = (-9.466666666667 m/sec²) ∆d </span>
<span>∆d = 66.0211267605634 m </span>
<span>∆d = 66.02 m</span>
7 0
3 years ago
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