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lutik1710 [3]
2 years ago
7

If 30.5 g of 15% potassium nitrate solution are reacted to excess magnesium chloride how many grams of potassium chloride will b

e form
Chemistry
1 answer:
Nata [24]2 years ago
4 0
Here the step by step and answer

You might be interested in
Which cannot be chemically broken down into simpler substances?
Anna71 [15]

Answer:

B.

Explanation:

elements

6 0
2 years ago
Read 2 more answers
Draw and label the parts of a helium atom. Include the mass and charge of each subatomic particle.
mihalych1998 [28]

Explanation:

Helium is the second element on the periodic table.

  Information about helium:

  • it belongs to group O on the periodic table
  • it is has an atomic number of 2
  • Helium exists naturally as gas and it is nonreactive.

  To write an atom we use this format:

                                     ₙᵇGˣ

   G is the symbol of the atom

   n is the atomic number  

   b is the mass number

    x is the charge on the atom

Using the periodic table as guide

    Symbol of helium is He

     Atomic number of helium is 2

     mass number of helium is 4

     charge on helium atom is 0

                              ⁴₂He

Every atom contains protons, neutrons and electrons;

   Electrons are negatively charged. For a neutral atom, the number of electrons is the same as that of protons.

   Protons are positively charge particles in an atom. The atomic number is the number of protons in an atom.

   neutrons do not have charges.

 

   Helium has:

        Number of protons = 2

        Number of electrons = 2

        Number of neutrons = 2

Mass of each subatomic particle:

      1 electron = 9.11 x 10⁻³¹kg

      2 electrons = 1.82 x 10⁻³⁰kg  

     Protons and neutrons have the same mass:

           1 proton = 1.67 x 10⁻²⁷kg

           2 protons = 3.34 x 10⁻²⁷kg

           2 neutrons = 3.34 x 10⁻²⁷kg

Learn more:

helium brainly.com/question/2439349

#learnwithBrainly

4 0
3 years ago
A gas stream containing n-hexane in nitrogen with a relative saturation of 0.58 (as a fraction, multiply by 100% if you prefer %
kondor19780726 [428]

This problem is describing a gas mixture whose mole fraction of hexane in nitrogen is 0.58 and which is being fed to a condenser at 75 °C and 3.0 atm, obtaining a product at 3.0 atm and 20 °C, so that the removed heat from the system is required.

In this case, it is recommended to write the enthalpy for each substance as follows:

H_{C-6}=y_{C-6}C_v(T_b-Ti)+\Delta _vH+C_v(T_f-Tb)\\\\H_{N_2}=y_{N_2}C_v(T_f-Ti)

Whereas the specific heat of liquid and gaseous n-hexane are about 200 J/(mol*K) and 160 J/(mol*K) respectively, its condensation enthalpy is 31.5 kJ/mol, boiling point is 69 °C and the specific heat of gaseous nitrogen is about 29.1 J/(mol*K) according to the NIST data tables and y_{C-6} and y_{N_2} are the mole fractions in the gaseous mixture. Next, we proceed to the calculation of both heat terms as shown below:

H_{C-6}=0.58*200(69-75)+(-31500)+160(20-69)=-40036J/mol\\\\H_{N_2}=0.42*29.1(20-75)=-672.21J/mol

It is seen that the heat released by the nitrogen is neglectable in comparison to n-hexanes, however, a rigorous calculation is being presented. Then, we add the previously calculated enthalpies to compute the amount of heat that is removed by the condenser:

Q=-40036+(-672.21)=-40708.21J

Finally we convert this result to kJ:

Q=-40708.21J*\frac{1kJ}{1000J}\\\\Q=-40.7kJ

Learn more:

  • brainly.com/question/25475410
  • brainly.com/question/12625048
6 0
2 years ago
If C and Cl combined to make a compound, would it be covalent or ionic?
arsen [322]

Answer:

it would be a covalent bond

Explanation:

carbon has 4 valence electrons, while chlorine has 7.

6 0
2 years ago
Gaseous butane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 4.1 g of butane is m
m_a_m_a [10]

Answer:

12.44 g

Explanation:

2C4H10 + 13O2 = 8CO2 + 10H2O

n(C4H10) = m(C4H10)/M(C4H10) = 4.1 / 58g/mol = 0.0707 mol (excess).

n(O2) = m(O2)/M(O2) = 25.9 / 32g/mol = 0.809 mol (deficiency).

Since the ratio of O2 to octane is 13 : 2 we can divide 0.0707 by 2 to get 0.03535 and divide 0.809 by 13 to get 0.062.

mass of CO2 produced =

M = [0.0707 moles C4H10 x 8 moles CO2] / 2 moles C4H10 x 44 g CO2/mol

M = 0.5656/2 * 44

M = 0.2828 * 44

M = 12.44 of CO2

5 0
2 years ago
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