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STatiana [176]
3 years ago
10

How many seconds would it take to deposit 17.3 g of ag (atomic mass = 107.87) from a solution of agno3 using a current of 10.00

amp?
a.3.09  103 s
b.7.74  102 s
c.4.64  103 s
d.1.55  103 s
e.5.16  102 s?
Chemistry
1 answer:
Brums [2.3K]3 years ago
5 0
Data Given:

Time = t = ?

Current = I = 10 A

Faradays Constant = F = 96500

Chemical equivalent = e = 107.86/1 = 107.86 g

Amount Deposited = W = 17.3 g

Solution:
             According to Faraday's Law,

                                          W  =  I t e / F

Solving for t,

                                          t  =  W F / I e
Putting values,
                                          t  =  (17.3 g × 96500) ÷ (10 A × 107.86 g)

                                          t  =  1547.79 s

                                          t  = 1.54 × 10³ s
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Here's how to do it: 

<span>Balanced equation first: </span>
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4 years ago
How many grams of kclo3 are needed to make 30.0 grams of kcl
lubasha [3.4K]

The mass of  potassium chlorate, KClO₃ needed to produce 30 grams of potassium chloride, KCl is 49.33 grams

<h3>Balanced equation </h3>

2KClO₃ —> 2KCl + 3O₂

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Mass of KClO₃ from the balanced equation = 2 × 122.5 = 245 g

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Mass of KCl from the balanced equation = 2 × 74.5 = 149 g

SUMMARY

From the balanced equation above,

149 g of KCl were obtained from 245 g of KClO₃

<h3>How to determine the mass of KClO₃ needed </h3>

From the balanced equation above,

149 g of KCl were obtained from 245 g of KClO₃

Therefore,

30 g of KCl will be obtained from = (30 × 245) / 149 = 49.33 g of KClO₃

Thus, 49.33 g of KClO₃ are needed for the reaction

Learn more about stoichiometry:

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