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klemol [59]
2 years ago
11

Is the chemical reaction, NaHCO3 ⇒ Na2CO3 + H2O + CO2, an example of combustion or an example of decomposition?

Chemistry
2 answers:
Lelu [443]2 years ago
6 0

Answer:

This chemical reaction is a <u>decomposition reaction this is because this reaction breaks up the chemical species breaking up into similar parts.</u>

<u>
hope I helped x
</u>

Tema [17]2 years ago
6 0

Answer:

it's decomposition

Explanation:

because it breaks up the chemical into smaller parts

You might be interested in
The reaction between iron(II) oxide and carbon monoxide produces iron and carbon dioxide. How many moles of iron can be obtained
My name is Ann [436]

Answer:

4.75 moles of Fe

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

FeO + CO —> Fe + CO2

Now, we can determine the number of mole of iron, Fe produced by the reaction of 4.75 mol of FeO with excess CO as follow:

From the balanced equation above,

1 mole of FeO reacted to produce 1 mole of Fe.

Therefore, 4.75 moles of FeO will also react to produce 4.75 moles of Fe.

Therefore, 4.75 moles of Fe is produced.

4 0
3 years ago
What is the pH for a solution that has an OH ion
Basile [38]
Assuming that you mean 10^-4 M then this would be basic and would have a pH of 10.

pOH = -log[OH].
So pOH = 4
pH=14-pOH
pH = 10
3 0
2 years ago
I2(g) + Cl2(g)2ICl(g) Using standard thermodynamic data at 298K, calculate the entropy change for the surroundings when 1.62 mol
galina1969 [7]

Answer:

The change in entropy of the surrounding is -146.11 J/K.

Explanation:

Enthalpy of formation of iodine gas = \Delta H_f_{(I_2)}=62.438 kJ/mol

Enthalpy of formation of chlorine gas = \Delta H_f_{(Cl_2)}=0 kJ/mol

Enthalpy of formation of ICl gas = \Delta H_f_{(ICl)}=17.78 kJ/mol

The equation used to calculate enthalpy change is of a reaction is:  

\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]

For the given chemical reaction:

I_2(g)+Cl_2(g)\rightarrow 2ICl(g),\Delta H_{rxn}=?

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(2\times \Delta H_f_{(ICl)})]-[(1\times \Delta H_f_{(I_2)})+(1\times \Delta H_f_{(Cl_2)})]

=[2\times 17.78 kJ/mol]-[1\times 0 kJ/mol+1\times 62.436 kJ/mol]=-26.878 kJ/mol

Enthaply change when 1.62 moles of iodine gas recast:

\Delta H= \Delta H_{rxn}\times 1.62 mol=(-26.878 kJ/mol)\times 1.62 mol=-43.542 kJ

Entropy of the surrounding = \Delta S^o_{surr}=\frac{\Delta H}{T}

=\frac{-43.542 kJ}{298 K}=\frac{-43,542 J}{298 K}=-146.11 J/K

1 kJ = 1000 J

The change in entropy of the surrounding is -146.11 J/K.

4 0
3 years ago
Can you Please answer this question?
olga2289 [7]

Answer:

first option is not true

Explanation:

1 mole = 6.02 × 10²³ particles

C3H8 has 1 mole, so has 6.02 × 10²³ particles

5O2 has 5 moles so 5 × 6.02 × 10²³ = 3.01 × 10²⁴ particles

3CO2 has 3 moles so 3 × 6.02 × 10²³ = 1.806 × 10²⁴ particles

4H2O has 4 moles so 4 × 6.02 × 10²³ = 2.408 × 10²⁴ particles

8 0
2 years ago
Calculate the relative density of carbon monoxide and carbon dioxide with respect to air.
JulsSmile [24]
Density is proportional to molar mass, assuming pressure and temperature remain constant. Therefore, since CO has a molar mass of 28 and CO2 has a molar mass of 44:
The relative density of CO vs air is 28/29 = 0.9655.
The relative density of CO2 vs air is 44/29 = 1.517.

3 0
3 years ago
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