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1 year ago

Is the chemical reaction, NaHCO3 ⇒ Na2CO3 + H2O + CO2, an example of combustion or an example of decomposition?

Chemistry

2 answers:

Lelu [443]1 year ago

6 0

Answer:

This chemical reaction is a decomposition reaction this is because this reaction breaks up the chemical species breaking up into similar parts.

hope I helped x

Tema [17]1 year ago

6 0

Answer:

it's decomposition

Explanation:

because it breaks up the chemical into smaller parts

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PLEASEEEE HELPPP ME WITH THISS

Ilia_Sergeevich [38]

Answer:

second law

Explanation:

6 0

3 years ago

3. After 7.9 grams of sodium are dropped into a bathtub full of water, how many grams of hydrogen gas are released?

Pavel [41]

Answer:

3) About 0.35 grams of hydrogen gas.

4) About 65.2 grams of aluminum oxide.

Explanation:

Question 3)

We are given that 7.9 grams of sodium is dropped into a bathtub of water, and we want to determine how many grams of hydrogen gas is released.

Since sodium is higher than hydrogen on the activity series, sodium will replace hydrogen in a single-replacement reaction for sodium oxide. Hence, our equation is:

$\displaystyle \text{Na} + \text{H$_2$O}\rightarrow \text{Na$_2$O}+\text{H$_2$}$

To balance it, we can simply add another sodium atom on the left. Hence:

$\displaystyle 2\text{Na} + \text{H$_2$O}\rightarrow \text{Na$_2$O}+\text{H$_2$}$

To convert from grams of sodium to grams of hydrogen gas, we can convert from sodium to moles of sodium, use the mole ratios to find moles in hydrogen gas, and then use hydrogen's molar mass to find its amount in grams.

The molar mass of sodium is 22.990 g/mol. Hence:

$\displaystyle \frac{1\text{ mol Na}}{22.990 \text{ g Na}}$

From the chemical equation, we can see that two moles of sodium produce one mole of hydrogen gas. Hence:

$\displaystyle \frac{1\text{ mol H$_2$}}{2\text{ mol Na}}$

And the molar mass of hydrogen gas is 2.016 g/mol. Hence:

$\displaystyle \frac{2.016\text{ g H$_2$}}{1\text{ mol H$_2$}}$

Given the initial value and the above ratios, this yields:

$\displaystyle 7.9\text{ g Na}\cdot \displaystyle \frac{1\text{ mol Na}}{22.990 \text{ g Na}}\cdot \displaystyle \frac{1\text{ mol H$_2$}}{2\text{ mol Na}}\cdot \displaystyle \frac{2.016\text{ g H$_2$}}{1\text{ mol H$_2$}}$

Cancel like units:

$=\displaystyle 7.9\cdot \displaystyle \frac{1}{22.990}\cdot \displaystyle \frac{1}{2}\cdot \displaystyle \frac{2.016\text{ g H$_2$}}{1}$

Multiply. Hence:

$=0.3463...\text{ g H$_2$}$

Since we should have two significant values:

$=0.35\text{ g H$_2$}$

So, about 0.35 grams of hydrogen gas will be released.

Question 4)

Excess oxygen gas is added to 34.5 grams of aluminum and produces aluminum oxide. Hence, our chemical equation is:

$\displaystyle \text{O$_2$} + \text{Al} \rightarrow \text{Al$_2$O$_3$}$

To balance this, we can place a three in front of the oxygen, four in front of aluminum, and two in front of aluminum oxide. Hence:

$\displaystyle3\text{O$_2$} + 4\text{Al} \rightarrow 2\text{Al$_2$O$_3$}$

To convert from grams of aluminum to grams of aluminum oxide, we can convert aluminum to moles, use the mole ratios to find the moles of aluminum oxide, and then use its molar mass to determine the amount of grams.

The molar mass of aluminum is 26.982 g/mol. Thus:

$\displaystyle \frac{1\text{ mol Al}}{26.982 \text{ g Al}}$

According to the equation, four moles of aluminum produces two moles of aluminum oxide. Hence:

$\displaystyle \frac{2\text{ mol Al$_2$O$_3$}}{4\text{ mol Al}}$

And the molar mass of aluminum oxide is 101.961 g/mol. Hence: $\displaystyle \frac{101.961\text{ g Al$_2$O$_3$}}{1\text{ mol Al$_2$O$_3$}}$

Using the given value and the above ratios, we acquire:

$\displaystyle 34.5\text{ g Al}\cdot \displaystyle \frac{1\text{ mol Al}}{26.982 \text{ g Al}}\cdot \displaystyle \frac{2\text{ mol Al$_2$O$_3$}}{4\text{ mol Al}}\cdot \displaystyle \frac{101.961\text{ g Al$_2$O$_3$}}{1\text{ mol Al$_2$O$_3$}}$

Cancel like units:

$\displaystyle= \displaystyle 34.5\cdot \displaystyle \frac{1}{26.982}\cdot \displaystyle \frac{2}{4}\cdot \displaystyle \frac{101.961\text{ g Al$_2$O$_3$}}{1}$

Multiply:

$\displaystyle = 65.1852... \text{ g Al$_2$O$_3$}$

Since the resulting value should have three significant figures:

$\displaystyle = 65.2 \text{ g Al$_2$O$_3$}$

So, approximately 65.2 grams of aluminum oxide is produced.

5 0

2 years ago

Read 2 more answers

Which isotope of lead has a double magic number? (1) Pb-206 (2) Pb-207 (3) Pb-208 (4) Pb-209

antiseptic1488 [7]

It is Pb-208, answer 3.

4 0

2 years ago

What is an azeotrope? 2. Under what conditions is it better to perform a steam distillation (instead of, say, a simple distillat

aleksandrvk [35]

Answer:

Explanation:

1.)azeotrope is a mixture of two or more liquid components under constant boiling, it has a constant mole fraction composition of present component which can be homogeneous or heterogeneous.

2.)the condition which it's best performed when there's liquids that is non-volatile which boils higher than other liquids with at least 26 degrees .

steam azentropic distillation

3.During a steam distillation, How to know if the organic compound is still coming over is when you see the solution becoming cloudy or when there is existence of two layers.

4.)The end of the steam distillation, the receiving flask should contain two layers of liquid, and the chemical identity of these two liquids most contain

A.) Layers that are mostly water H2O

B.) Layers that are mostly products

5.)What is the purpose of adding 10% sodium carbonate solution to the distillate if it is acidic to litmus is to neutralize the distillate.

7 0

3 years ago

The magnitude of an earthquake, measured on the Richter Scale, is M log1o T where / is the amplitude registered on a seismograph

just olya [345]

Answer: The magnitude rating for an earthquake causing an amplitude 10,000,000 times $I_o$ is 7.

Explanation:

Richter scale is defined as the scale which expresses the magnitude of earthquake on the basis of the seismograph oscillations.

The equation used to measure the magnitude of an earthquake on Richter scale is:

$M=log_{10}\frac{I}{I_o}$

where

I = amplitude registered on seismograph 100 km away from seismic center = $10,000,000I_o$

$I_o$ = small amplitude

Putting values in above equation, we get:

$M=\log_{10}(\frac{10000000I_o}{I_o})\\\\M=7$

Hence, the magnitude rating for an earthquake causing an amplitude 10,000,000 times $I_o$ is 7.

8 0

3 years ago