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2 years ago

Is the chemical reaction, NaHCO3 ⇒ Na2CO3 + H2O + CO2, an example of combustion or an example of decomposition?

Chemistry

2 answers:

Lelu [443]2 years ago

6 0

Answer:

This chemical reaction is a <u>decomposition reaction this is because this reaction breaks up the chemical species breaking up into similar parts.</u>

<u>
hope I helped x</u>

Tema [17]2 years ago

6 0

Answer:

it's decomposition

Explanation:

because it breaks up the chemical into smaller parts

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The reaction between iron(II) oxide and carbon monoxide produces iron and carbon dioxide. How many moles of iron can be obtained

My name is Ann [436]

Answer:

4.75 moles of Fe

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

FeO + CO —> Fe + CO2

Now, we can determine the number of mole of iron, Fe produced by the reaction of 4.75 mol of FeO with excess CO as follow:

From the balanced equation above,

1 mole of FeO reacted to produce 1 mole of Fe.

Therefore, 4.75 moles of FeO will also react to produce 4.75 moles of Fe.

Therefore, 4.75 moles of Fe is produced.

4 0

3 years ago

What is the pH for a solution that has an OH ion

Basile [38]

Assuming that you mean 10^-4 M then this would be basic and would have a pH of 10.

pOH = -log[OH].
So pOH = 4
pH=14-pOH
pH = 10

3 0

2 years ago

I2(g) + Cl2(g)2ICl(g) Using standard thermodynamic data at 298K, calculate the entropy change for the surroundings when 1.62 mol

galina1969 [7]

Answer:

The change in entropy of the surrounding is -146.11 J/K.

Explanation:

Enthalpy of formation of iodine gas = $\Delta H_f_{(I_2)}=62.438 kJ/mol$

Enthalpy of formation of chlorine gas = $\Delta H_f_{(Cl_2)}=0 kJ/mol$

Enthalpy of formation of ICl gas = $\Delta H_f_{(ICl)}=17.78 kJ/mol$

The equation used to calculate enthalpy change is of a reaction is:

$\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]$

For the given chemical reaction:

$I_2(g)+Cl_2(g)\rightarrow 2ICl(g),\Delta H_{rxn}=?$

The equation for the enthalpy change of the above reaction is:

$\Delta H_{rxn}=[(2\times \Delta H_f_{(ICl)})]-[(1\times \Delta H_f_{(I_2)})+(1\times \Delta H_f_{(Cl_2)})]$

$=[2\times 17.78 kJ/mol]-[1\times 0 kJ/mol+1\times 62.436 kJ/mol]=-26.878 kJ/mol$

Enthaply change when 1.62 moles of iodine gas recast:

$\Delta H= \Delta H_{rxn}\times 1.62 mol=(-26.878 kJ/mol)\times 1.62 mol=-43.542 kJ$

Entropy of the surrounding = $\Delta S^o_{surr}=\frac{\Delta H}{T}$

$=\frac{-43.542 kJ}{298 K}=\frac{-43,542 J}{298 K}=-146.11 J/K$

1 kJ = 1000 J

The change in entropy of the surrounding is -146.11 J/K.

4 0

3 years ago

Can you Please answer this question?

olga2289 [7]

Answer:

first option is not true

Explanation:

1 mole = 6.02 × 10²³ particles

C3H8 has 1 mole, so has 6.02 × 10²³ particles

5O2 has 5 moles so 5 × 6.02 × 10²³ = 3.01 × 10²⁴ particles

3CO2 has 3 moles so 3 × 6.02 × 10²³ = 1.806 × 10²⁴ particles

4H2O has 4 moles so 4 × 6.02 × 10²³ = 2.408 × 10²⁴ particles

8 0

2 years ago

Calculate the relative density of carbon monoxide and carbon dioxide with respect to air.

JulsSmile [24]

Density is proportional to molar mass, assuming pressure and temperature remain constant. Therefore, since CO has a molar mass of 28 and CO2 has a molar mass of 44:
The relative density of CO vs air is 28/29 = 0.9655.
The relative density of CO2 vs air is 44/29 = 1.517.

3 0

3 years ago