Answer:
o
Explanation:
The athlete ran a total distance of zero because they ran 100m forward then turned around so they went back to their starting position
Answer:
yes
Explanation:
The solubility of glucose at 30°C is
125 g/100 g water. Classify a solution made by adding 550 g of glucose to 400 mL of water at 30°C. Explain your classification, and describe how you could increase the amount of glucose in the solution without adding more glucose.
The mechanisms of reproductive isolation are:
1) Habitat isolation
2) Behavioral isolation
3) Mechanical isolation
4) Gametic isolation
The isolation happening here is behavioral isolation, because their different behavior patterns prevent the frogs from breeding.
Answer:
d = 13 miles
Explanation:
Lets say the position of court house is origin in this case
her office is located at 4 miles west and 4 miles south of court house
so here we have coordinate of the office with respect to court house is given as

now the position of her home is located at 1 miles east and 8 miles north of the court house
so the coordinates of her home is given as

now the change in the position is given as the distance between office and home



Solution :
Given weight of Kathy = 82 kg
Her speed before striking the water,
= 5.50 m/s
Her speed after entering the water,
= 1.1 m/s
Time = 1.65 s
Using equation of impulse,

Here, F = the force ,
dT = time interval over which the force is applied for
= 1.65 s
dP = change in momentum
dP = m x dV
![$= m \times [V_f - V_o] $](https://tex.z-dn.net/?f=%24%3D%20m%20%5Ctimes%20%5BV_f%20-%20V_o%5D%20%24)
= 82 x (1.1 - 5.5)
= -360 kg
∴ the net force acting will be


= 218 N