The Andromeda Galaxy (our nearest spiral neighbor) has spectral lines that show a blue shift. From this we may conclude that:
1 answer:
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Answer:
(A) The spring constant is <u>98 N/m.</u>
(B) The period of oscillation is <u>0.635 s.</u>
Explanation:
Given:
Mass of the body is,
Extension length of the spring is,
Now, let 'k' be the spring constant.
The force acting on the body is due to gravity only and is equal to its weight.
So, weight of the body is given as:
Now, we know that for a spring-mass system, the net force acting on the body is equal to the product of the spring constant and extension length. Therefore,
Hence, the spring constant is 98 N/m.
(B)
Period of oscillation of a body of spring-mass system in SHM is given as:
Plug in the given values and solve for period 'T'. This gives,
Therefore, the period of oscillation is 0.635 s.
Answer:
n the case of linear motion, the change occurs in the magnitude of the velocity, the direction remaining constant.
In the case of circular motion, the magnitude of the velocity remains constant, the change in its direction occurring.
Explanation:
Velocity is a vector therefore it has magnitude and direction, a change in either of the two is the consequence of an acceleration on the system.
In the case of linear motion, the change occurs in the magnitude of the velocity, the direction remaining constant.
= (v₂-v₁)/Δt
In the case of circular motion, the magnitude of the velocity remains constant, the change in its direction occurring.
= v2/R
In the general case, both the module and the address change
a = Ra ( a_{t}^2 + a_{c}^2)