A school bus is headed on a field trip to LA traveling at 55 mph. Robert is

Green light (λ = 566 nm) strikes a single slit at normal incidence. Part A

VARVARA [1.3K]

Answer:

755 x 10⁻⁷ m

Explanation:

D = distance of screen

=2. m

d is width of slit = ?

wave length λ = 566 nm

Width of central maxima = 2 λD /d

= 3.00 x 10⁻² =2 λD /d

$d=\frac{2\times566\times10^{-9}\times2}{3\times10^{-2}}$

= 754.67 x 10⁻⁷ m .

= 755x 10⁻⁷ m

8 0

3 years ago

A body can have zero average velocity but not zero average speed. Why?

bogdanovich [222]

Displacement can be zero so velocity is zero but the distance won’t be zero so speed won’t be zero

5 0

3 years ago

PLS ANSWER FAST WILL GIVE BRAINLY!!!!!!!

Ivahew [28]

Answer:

the answer is the explaination

Explanation:

Present beach erosion prevention methods include sand dunes, vegetation, seawalls, sandbags, and sand fences. Based on the research conducted, it is evident that new ways to prevent erosion must be obtained. Each way that is currently used has extensive negative effects on beaches and their natural tendencies.

4 0

3 years ago

Read 2 more answers

A woman sits on a spinning piano stool with her arms extended. When she folds her arms, which of the following occurs? Question

iogann1982 [59]

Answer:

The correct option is that (She decreases her moment of inertia, thereby increasing her angular speed.)

Explanation:

When an object is in circular motion, the vector that describes it is known as angular momentum. Angular momentum is conserved or constant when an object is spinning in a closed system and no external torques are applied to it. An example of conservation of angular momentum is seen when a woman is sitting on a spinning piano stool with her arms extended. Her angular momentum is conserved because the net torque on her is negligibly small as the friction is exerted very close to the pivot point.

When she folds her arms,her rate of spin increases greatly decreasing her moment of inertia. The work she does to pull in her arms results in an increase in rotational kinetic energy( that is, increase in her angular speed). I hope this helps, thanks!

5 0

3 years ago

A 1.1 kg ball is attached to a ceiling by a 2.16 m long string. The height of the room is 5.97 m . The acceleration of gravity i

nydimaria [60]

1. -23.2 J

The gravitational potential energy of the ball is given by

$U=mgh$

where

m = 1.1 kg is the mass of the ball

g = 9.8 m/s^2 is the acceleration of gravity

h is the height of the ball, relative to the reference point chosen

In this part of the problem, the reference point is the ceiling. So, the ball is located 2.16 m below the ceiling: therefore, the heigth is

h = -2.16 m

And the gravitational potential energy is

$U=(1.1 kg)(9.8 m/s^2)(-2.16 m)=-23.2 J$

2. 41.1 J

Again, the gravitational potential energy of the ball is given by

$U=mgh$

In this part of the problem, the reference point is the floor.

The height of the ball relative to the floor is equal to the height of the floor minus the length of the string:

h = 5.97 m - 2.16 m = 3.81 m

And so the gravitational potential energy of the ball relative to the floor is

$U=(1.1 kg)(9.8 m/s^2)(3.81 m)=41.1 J$

3. 0 J

As before, the gravitational potential energy of the ball is given by

$U=mgh$

Here the reference point is a point at the same elevation of the ball.

This means that the heigth of the ball relative to that point is zero:

h = 0 m

And so the gravitational potential energy is

$U=(1.1 kg)(9.8 m/s^2)(0 m)=0 J$

4 0

4 years ago