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2 years ago

What is the equation of the circle with center (-3.2, -2.1) and radius 4.3?

Mathematics

1 answer:

Ilya [14]2 years ago

6 0

The equation of the circle is : $x^{2}$ + $y^{2}$ + 6.4 $x$ + 4.2 $y$ = 3.84

<h3>Meaning of a Circle</h3>

A circle is a loci or a continuous line that equidistant from the center to any point on the line. it drawn starting from a point and ending on that same point.

The equation of a circle is an equation used to find points on a circle so the circle can be drawn with accurate measurement. it can also be used to find the missing points.

In conclusion, The equation of the circle is : $x^{2}$ + $y^{2}$ + 6.4 $x$ + 4.2 $y$ = 3.84

Learn more about equation of a circle: brainly.com/question/1506955

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3 years ago

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3 years ago

Csc (2sin^-1(-12/13))<br> that is 2 times inverse sin of -12/13

german

Answer: $-\frac{169}{120}$

I'm assuming you mean this:

$cosec(2sin^{-1}(\frac{-12}{13}))$

Recall what the cosecant function represents. It is the reciprocal of a sine function, and is often written in this form:

$\frac{1}{sinx}$

So, using the sine relationship:

$cosec(2sin^{-1}(\frac{-12}{13})) = \frac{1}{sin(2sin^{-1}(\frac{-12}{13}))}$

Let $u = sin^{-1}(\frac{-12}{13})$
$cosec(2sin^{-1}(\frac{-12}{13})) = \frac{1}{sin(2u)}$
$= \frac{1}{2sinu \cdot cosu}$
$= \frac{1}{2sin(sin^{-1}(\frac{-12}{13})) \cdot cos(sin^{-1}(\frac{-12}{13}))}$
$= \frac{1}{\frac{-24}{13} \cdot \sqrt{1 - (\frac{-12}{13})^{2}}}$
$= \frac{1}{\frac{-24}{13}} \cdot \frac{1}{\sqrt{1 - \frac{144}{169}}}$
$= -\frac{13}{24} \cdot \frac{1}{\sqrt{\frac{25}{169}}}$
$= -\frac{13}{24} \cdot \frac{1}{\frac{5}{13}}$
$= -\frac{13}{24} \cdot \frac{13}{5}$
$= -\frac{169}{120}$

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3 years ago