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2 years ago

60. How can a colloid be destroyed?

Chemistry

1 answer:

PIT_PIT [208]2 years ago

7 0

$\mathbb\color{cyan}{\tiny A\scriptsize N\small S\large W\Large E\huge R}$

by adding ions with a charge opposite that of the colloidal particles.

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List 4 signs that show evidence of a chemical reaction

Gnoma [55]

Change in color, change in temp, formation of gas, or formation of precipitate

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3 years ago

How many moles are equal to 3.15x10^23 molecules of ethyne, C2H2?

vlabodo [156]

Answer:

0.523 moles

Explanation:

(3.15×10²³) / (6.022×10²³)= 0.523 moles

5 0

3 years ago

MAX TEN MINUTES PLZZZZZ HURRY

Marianna [84]

Answer:

when it reduces heat.

Explanation:

Thermal energy is transferred to material,the motion of its particles speeds up and it's temperature differences.Insulating materials are bad conductors and so this reduces the heat loss by conduction.The material also prevents air circulating inside the cavity,therefore reducing heat loss by convection.Heat loss through the roof can be reduced by laying loft insulation.

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3 years ago

When an ionic compound such as sodium chloride (NaCl) is placed in water the component atoms of the NaCl crystal dissociate into

sammy [17]

Answer:

Solution (C) contains greatest number of particles.

Explanation:

Molarity of a solution = (no. of moles of solute in solution)/(volume of solution in liter). Here, NaCl and glucose are solutes.

1 mol = $6.023\times 10^{23}$ number of molecules/ions

Glucose is a non-electrolyte and NaCl is an electrolyte

So, 1 mol glucose = $6.023\times 10^{23}$ number of molecules of glucose

1 mol NaCl = $1.205\times 10^{24}$ number of ions

Solution moles of solute (molarity $\times$ volume) no. of particles

A 0.5 $6.023\times 10^{23}$

B 0.5 $3.012\times 10^{23}$

C 1.0 $1.205\times 10^{24}$

D 1.0 $6.023\times 10^{23}$

So, solution (C) contains greatest number of particles

6 0

3 years ago

What mass of methanol (Ch3OH) is produced when 86.04 of carbon monoxide reacts with 14.14g of hydrogen

solmaris [256]

Answer:

98.33 g of CH3OH

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

CO(g) + 2H2(g) —> CH3OH(l)

Step 2:

Determination of the masses of CO and H2 that reacted and the mass of CH3OH produced from the balanced equation.

This can be obtained as follow:

Molar mass of CO = 12 + 16 = 28 g/mol

Mass of CO from the balanced equation = 1 x 28 = 28 g

Molar mass of H2 = 2x1 = 2 g/mol

Mass of H2 from the balanced equation = 2 x 2 = 4 g

Molar mass of CH3OH = 12 + (3x1) + 16 + 1 = 32 g/mol

Mass of CH3OH from the balanced equation = 1 x 32 = 32 g.

Summary:

From the balanced equation above,

28 g of CO reacted with 4 g of H2 to produce 32 g of CH3OH.

Step 3:

Determination of the limiting reactant.

This can be obtained as follow:

From the balanced equation above,

28 g of CO reacted with 4 g of H2.

Therefore, 86.04 g of CO will react with = (86.04 x 4)/28 = 12.29 g of H2.

From the calculation made above, only 12.29 g out of 14.14 g of H2 given were required to react completely with 86.04 g of CO.

Therefore, CO is the limiting reactant and H2 is the excess reactant.

Step 4:

Determination of the mass of methanol, CH3OH produced from the reaction.

In this case the limiting reactant shall be used because it will give the maximum yield of methanol, CH3OH since all of it were consumed in the reaction.

The limiting reactant is CO and the mass of methanol, CH3OH produced can be obtained as follow:

From the balanced equation above,

28 g of CO reacted to produce 32 g of CH3OH.

Therefore, 86.04 g of CO will react to produce = (86.04 x 32)/28 = 98.33 g

Therefore, 98.33 g of CH3OH were obtained from the reaction.

5 0

4 years ago