From the density of ethanol given, the number of pounds of ethanol in the drum will be 46.099 pounds.
<h3>How to calculate density</h3>
Density of ethanol = 0.789/cm³
1 gallon = 3785.4ml
Volume of ethanol = 7 gallons = 7 × 3785.4ml = 26497.8ml
Mass of ethanol = Volume × Density.
= 26497.8 × 0.789
= 20906.764g
Since 1g = 0.002205 pounds, the mass of ethanol will be:
= 20906.764 × 0.002205
= 46.099 pounds.
Learn more about density on:
brainly.com/question/11730603
Answer:
259.08
Explanation:
if you see 102 times 2.54 = that number is right answer
The required mass of argon in given number of atoms of argon is 155.61 grams.
<h3>What is Avogadro's number?</h3>
Avogadro's number is the number of atoms which are present in 1 mole of any substance and it is equal to 6.022×10²³.
Relation between the mass and moles of any substance will be represented as:
- n = W/M, where
- W = given mass
- M = molar mass
So, moles of argon will be calculated by using given number of atoms as:
Moles = 2.4×10²⁴ atoms / 6.022×10²³ atoms per mole
Moles = 3.9 moles
Now mass will be:
W = (3.9mol)(39.9g/mol) = 155.61 g
Hence required mass of argon is 155.6g.
To know more about Avogadro's number, visit the below link:
brainly.com/question/1513182
#SPJ1
