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Eduardwww [97]
4 years ago
6

Indicate whether or not you can determie the element name using ONLY the following

Chemistry
1 answer:
Anit [1.1K]4 years ago
5 0

Answer:

As long as the number of protons per nucleus is known, the name of the element can be determined.

Explanation:

Knowing only the number of neutrons per nucleus alone isn't enough for finding the name of the element. For example, both hydrogen-2 and helium-3 contain one neutron per nucleus. However, these hydrogen and helium are two different elements.

Similarly, the number of electrons alone isn't sufficient for finding the name of the element. For example, both sodium ions \rm Na^+ and neon atoms \rm Ne contain 10 electrons per particle. However, sodium and neon are different elements.

Once the number of protons in an atom or ion is known, simply look up that number on the periodic table of elements. There's one-to-one correlation between the number of protons and the name of the element. For example, if an atom contains 2 protons, its atomic number on the periodic table would also be 2. That corresponds to the element helium.

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I need help solving this chemistry question ​
Arturiano [62]

Answer:

I think the answer is 22.2

Explanation: What i DID was adding 12.0 + 10.0 and than that gave me 22 the I had added the to 0.200 and that how i got 22.2. Sorry if i got is wrong. :(

3 0
4 years ago
If 12.5 grams of the original sample of cesium-137 remained after 90.6 years, what was the mass of the original sample?
myrzilka [38]

Answer:

Mass of original sample = 100 g

Explanation:

Half life of cesium-137 = 30.17 years

t_{1/2}=\frac {ln\ 2}{k}

Where, k is rate constant

So,  

k=\frac{\ln2}{t_{1/2}}

k=\frac{\ln2}{30.17}\ year^{-1}

The rate constant, k = 0.02297 year⁻¹

Time = 90.6 years

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

Initial concentration [A_0] = ?

Final concentration [A_t] = 12.5 grams

Applying in the above equation, we get that:-

12.5\ g=[A_0]e^{-0.02297\times 90.6}

[A_0]=\frac{12.5}{e^{-0.02297\times 90.6}}\ g=100\ g

<u>Mass of original sample = 100 g</u>

8 0
3 years ago
The pH of a vinegar solution is 4.15. What is the H+ concentration of the solution
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The Only Viable Solution: A New Moon Shot

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