Indicate whether or not you can determie the element name using ONLY the following

Chemistry

1 answer:

Anit [1.1K]4 years ago

5 0

Answer:

As long as the number of protons per nucleus is known, the name of the element can be determined.

Explanation:

Knowing only the number of neutrons per nucleus alone isn't enough for finding the name of the element. For example, both hydrogen-2 and helium-3 contain one neutron per nucleus. However, these hydrogen and helium are two different elements.

Similarly, the number of electrons alone isn't sufficient for finding the name of the element. For example, both sodium ions $\rm Na^+$ and neon atoms $\rm Ne$ contain 10 electrons per particle. However, sodium and neon are different elements.

Once the number of protons in an atom or ion is known, simply look up that number on the periodic table of elements. There's one-to-one correlation between the number of protons and the name of the element. For example, if an atom contains 2 protons, its atomic number on the periodic table would also be 2. That corresponds to the element helium.

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The activation energy for the reaction NO2(g)+CO(g)⟶NO(g)+CO2(g) is Ea = 375 kJ/mol and the change in enthalpy for the reaction

HACTEHA [7]

Answer: 625 kj/mol

Explanation:

As shown below this expression gives the activation energy of the reverse reaction:

EA reverse reaction = EA forward reaction + | enthalpy change |

1) The activation energy, EA is the difference between the potential energies of the reactants and the transition state:

EA = energy of the transition state - energy of the reactants.

2) The activation energy of the forward reaction given is:

EA = energy of the transition state - energy of [ NO2(g) + CO(g) ] = 75 kj/mol

3) The negative enthalpy change - 250 kj / mol for the forward reaction means that the products are below in the potential energy diagram, and that the potential energy of the products, [NO(g) + CO2(g) ] is equal to 375 kj / mol - 250 kj / mol = 125 kj/mol

4) For the reverse reaction the reactants are [NO(g) + CO2(g)], and the transition state is the same than that for the forward reaction.

5) The difference of energy between the transition state and the potential energy of [NO(g) + CO2(g) ] will be the absolute value of the change of enthalpy plus the activation energy for the forward reaction:

EA reverse reaction = EA forward reaction + | enthalpy change |

EA reverse reaction = 375 kj / mol + |-250 kj/mol | = 375 kj/mol + 250 kj/mol = 625 kj/mol.

And that is the answer, 625 kj/mol

4 0

3 years ago

An object has a volume of 825 cm3 and a density of 13.6 g/cm3. Find its<br> mass

lara [203]

Answer: 11,200 g

step by step explanation:

D= M/V
M= DV
M= (13.6 g/cm^3) (825cm^3)
M= 11,200 g

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3 years ago

Which elements have electron configurations that end in ns 2 np 5 ? halogens noble gases inner transition metals transition meta

4vir4ik [10]

HALOGENS have 7 electrons in their final shell regardless if the total number of atoms. These 7 electrons would be shared between the 's' and 'p' orbital in the form ns² np⁵ (the same as the question). Attached is a table that highlights the fact that halogens have the same form in terms of the valence electrons.

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3 years ago

What is the enthalpy for 2H2S(g) + 3O2(g) -> 2H2O(I) + 2SO2(g). (∆H)

miss Akunina [59]

Answer:

2H2S (g) + 3O2 (g) → 2H2O (l) + 2SO2 (g)

Calculate ΔH° from the given data. Is the reaction exothermic or endothermic?

ΔH°f (H2S) = -20.15 kJ/mol; ΔH°f (O2) = 0 kJ/, mol; ΔH°f (H2O) = -285.8 kJ/mol; ΔH°f (SO2) = -296.4 kJ/mol

8 0

3 years ago

3. Which part of Thomson's plum pudding model was different from Rutherford's model?

horsena [70]

Answer:

The difference between the Thompson's plum pudding model and the Rutherford atom model is the location of the electrons (option a).

Explanation:

While Thompson compared his atom to a plum pudding, where the electrons floated freely in the pudding, Rutherford established the arrangement of the electrons in orbitals, which were found around the atomic nucleus like the planets around the sun.

Rutherford's findings also established the existence of a small, positively charged nucleus.

<em>Thompson and Rutherford models did not differentiate between the charges of electrons and protons , overall charges or overall size of the atom.</em>

8 0

3 years ago