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labwork [276]
4 years ago
8

The net ionic equation for formation of an aqueous solution of NiI 2 accompanied by evolution of CO 2 gas via mixing solid NiCO

3 and aqueous hydriodic acid is ________. 2NiCO3 (s) HI (aq) 2H2O (l) CO2 (g) 2Ni2 (aq) NiCO3 (s) I- (aq) 2H2O (l) CO2 (g) Ni2 (aq) HI (aq) NiCO3 (s) 2H (aq) H2O (l) CO2 (g) Ni2 (aq) NiCO3 (s) 2HI (aq) 2H2O (l) CO2 (g) NiI2 (aq) NiCO3 (s) 2HI (aq) H2O (l) CO2 (g) Ni2 (aq) 2I- (aq)
Chemistry
1 answer:
Naily [24]4 years ago
6 0

Answer:NiCO_3(s)+2H^+(aq)\rightarrow Ni^{2+}(aq)+CO_2(g)+H_2O(l)

Explanation:

Spectator ions are defined as the ions which does not get involved in a chemical equation or they are ions which are found on both the sides of the chemical reaction present in ionic form.

The balanced chemical equation will be:

NiCO_3(s)+2HI(aq)\rightarrow NiI_2(aq)+CO_2(g)+H_2O(l)

The total ionic chemical equation will be:

NiCO_3(s)+2H^+(aq)+2I^-(aq)\rightarrow Ni^{2+}(aq)+2I^-(aq)+CO_2(g)+H_2O(l)

The ions which are present on both the sides of the equation are iodide ions and hence are not involved in net ionic equation.

NiCO_3(s)+2H^+(aq)\rightarrow Ni^{2+}(aq)+CO_2(g)+H_2O(l)

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What is the density of CHCL3 vapor at 1.00atm and 298K?
Advocard [28]

Answer:

4.8 g/mL is the density of chloroform vapor at 1.00 atm and 298 K.

Explanation:

By ideal gas equation:

PV=nRT

Number of moles (n)

can be written as: n=\frac{m}{M}

where, m = given mass

M = molar mass

PV=\frac{m}{M}RT\\\\PM=\frac{m}{V}RT

where,

\frac{m}{V}=d which is known as density of the gas

The relation becomes:

PM=dRT    .....(1)

We are given:

M = molar mass of chloroform= 119.5 g/mol

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = temperature of the gas = 298K

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Putting values in equation 1, we get:

1.00atm\times 119.5g/mol=d\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 298K\\\\d=4.88g/L

4.8 g/mL is the density of chloroform vapor at 1.00 atm and 298 K.

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