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An equilibrium mixture contains 0.750 mol of each of the products (carbon dioxide and hydrogen gas) and 0.200 mol of each of the

sasho [114]

1.302 moles of carbon dioxide would have to be added

<h3>Further explanation</h3>

The equilibrium constant is the value of the product in the equilibrium state of the substance in the right (product) divided by the substance in the left (reactant) with the exponents of each reaction coefficient

The equilibrium constant is based on the concentration (Kc) in a reaction

pA + qB -----> mC + nD

$\large {\boxed {\bold {Kc ~ = ~ \frac {[C] ^ m [D] ^ n} {[A] ^ p [B] ^ q}}}}$

While the equilibrium constant is based on partial pressure

$\large {\boxed {\bold {Kp ~ = ~ \frac {[pC] ^ m [pD] ^ n} {[pA] ^ p [pB] ^ q}}}}$

The value of Kp and Kc can be linked to the formula '

$\large {\boxed {\bold {Kp ~ = ~ Kc. (R.T) ^ {\Delta n}}}}$

R = gas constant = 0.0821 L.atm / mol.K

=n = number of product coefficients-number of reactant coefficients

An equilibrium mixture: 0.750 moles of CO2 and H2, and 0.200 moles of CO and H2O

We determine Kc (constant concentration)

$\displaystyle Kc=\frac{0.75.0.75}{0.2.0.2}\\\\Kc=14.1$

the amount of carbon monoxide to 0.300 mol

Reaction :

CO +H₂O ⇔ CO₂ + H₂

initially 0.2 0.2 0.75+x 0.75

reaction 0.1 0.1 0.1 0.1

product 0.3 0.3 0.65+x 0.65

$\displaystyle Kc=\frac{(0.650+x)(0.65)}{0.3.0.3}\\\\14.1(0.09)=0.4225+0.65x\\\\1.269-0.4225=0.65x\\\\0.8465=0.65x\\\\x=1.302$

<h3>Learn more</h3>

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Keywords: constant equilibrium, Kc, concentration, product, reactant, reaction coefficient

3 0

4 years ago

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One symptom of carbon monoxide poisoning is the development of Mees lines on the fingernails and toenails.

satela [25.4K]

Mees' lines are white bands that form across your fingernails and are one of the symptoms of carbon monoxide poisoning.

Mees' lines are a sign that the growth of your nails temporarily stopped at one point. There are many causes to Mees' lines, and usually it indicates a toxicity. Carbon monoxide, along with other substances like arsenic, and selenium poisoning may cause them.

3 0

3 years ago

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The temperature of a freezer started at 18şc. After cooling for a few hours, the freezer had a temperature of –12şc. What is the

andre [41]

20 minus 2 plus 1 equals negative -2000000

8 0

3 years ago

When a non metal gains or shares by two electrons,its valency will be

Assoli18 [71]

When a non metal gains or share by two electrons then the valency will be 2^- or 2^+

8 0

3 years ago

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Can someone explain the steps for balancing chemical equations in depth?

m_a_m_a [10]

Answer:

Steps explained below

Explanation:

To explain balancing of chemical equations, I will make use of an example equation where Hydrogen and oxygen react to form water.

H2 + O2 = H2O

Now, the equation I've listed above is an unbalanced chemical equation. It can be balanced by the following steps;

Step 1: Identify the elements on both the left Hand side and the right hand side.

In this case;

on the left hand side, we have H and O.

On the right hand side, we have H and I also.

Step 2: Identify the number of atoms of each element on both the left and right hand sides.

On the left, H has 2 atoms and O has 2 atoms.

On the right, H has 2 atoms and O has 1 atom.

Step 3: For the equation to be balanced, the number of atoms of each element on the right and left hand side must be the same.

Thus,

O on the left hand side has 2 atoms but on the right hand side it has 1 atom. Thus, we will multiply O on the right by 2 to balance what we have on the left.

So, we now have;

H2 + O2 = 2H2O

Step 4: Check equation: We now have;

H2 + O2 = 2H2O

Our left hand side remains 2 atoms of H and 2 atoms of O. But on the right, we now have;

2 atoms O and 4 atoms of H.

Which means atoms of H is not balanced with the left side.

Step 5: rebalance equation: To rebalance, we multiply H on the left by 2 to give us 2 × 2 = 4 atoms.

Thus, we now have;

2H2 + O2 = 2H2O

3 0

3 years ago

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