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Darya [45]
3 years ago
13

He total power used by humans worldwide is approximately 15 TW (terawatts). Sunlight striking Earth provides 1.336 kW per square

meter (assuming no clouds). The surface area of Earth is approximately 197,000,000 square miles.
What percentage of the Earth's surface would we need to cover with solar energy collectors to power the planet for use by all humans? Assume that the solar energy collectors can only convert 10 % of the available sunlight into useful power.
Chemistry
1 answer:
SCORPION-xisa [38]3 years ago
3 0

Answer:

id

Explanation:

idk

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How many molecules are in 0.288 moles of water?
iragen [17]

Answer:

for every 1 mole you multiply 6.02 x 10^23

Explanation:

3 0
3 years ago
how many calories of energy are given off to lower the temperature of 100.0g of iron from 150.0°C to 35.0°C?
jeyben [28]

Answer:

ΔT = Tfinal − Tinitial = 150°C − 35.0°C = 125°C

given the specific heat of iron as 0.108 cal/g·°C

heat=(100.0 g)(0.108 cal /g· °C )(125°C) =

  100x 0.108x125= 1350 cal

4 0
3 years ago
Isotopes are atoms of an element
stellarik [79]
D. With the same number of protons and different number of neutrons.
6 0
3 years ago
In which part of the cell is the majority of the energy released from the breakdown of glucose
Vladimir [108]

<em>Answer</em><em>:</em>

<em>Glycolysis</em>

<em>E</em><em>xplanation</em><em> </em><em>:</em>

Glycolysis is the first step in the breakdown of glucose to extract energy for cell metabolism.Many living organisms carry out glycolysis as part of their metabolism. Glycolysis takes place in the cytoplasm of most prokaryotic and all eukaryotic cells.

7 0
3 years ago
Read 2 more answers
A volume of 90.0 mL of aqueous potassium hydroxide (KOH) was titrated against a standard solution of sulfuric acid (H2SO4). What
Gemiola [76]

Answer:

The answer to your question:  0.7 M

Explanation:

Data

V of KOH = 90 ml

[KOH] = ?

V H2SO4 = 21.2 ml

[H2SO4] = 1.5 M

                       2KOH(aq)  +  H₂SO₄(aq)   →   K₂SO₄(aq)  +  2H₂O(l)

Molarity = moles / volume

moles of H₂SO₄ = (1.5) (21.2)

                           = 31.8

                    2 moles of KOH --------------  1 mol of H₂SO₄

                   x                           --------------  31.8 mol of H₂SO₄

                    x = (31.8)(2) / 1

                    x = 63.8 moles of KOH

Molarity = 63.8 / 90

             = 0.7 M

7 0
3 years ago
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