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Dima020 [189]
2 years ago
10

To which period does an element belong if it has its 3d orbitals filled

Chemistry
1 answer:
swat322 years ago
4 0

fourth period

The third period is similar to the second, except the 3s and 3p sublevels are being filled. Because the 3d sublevel does not fill until after the 4s sublevel, the fourth period contains 18 elements, due to the 10 additional electrons that can be accommodated by the 3d orbitals.

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25.00 mL of a H2SO4 solution with an unknown concentration was titrated to a phenolphthalein endpoint with 28.11 mL of a 0.1311
LuckyWell [14K]

Answer:

Concentration of the H₂SO₄ solution is 0.0737 M

Explanation:

Equation of the neutralization reaction between the acid, H₂SO₄, and the base, NaOH, is given below:

H₂SO₄ + 2NaOH -----> Na₂SO₄ + 2H₂O

From the above equation, one mole of acid requires 2 moles of base for complete neutralization which occurs at phenolphthalein endpoint.

mole ratio of acid to base, nA/nB = 1:2

Concentration of the base, Cb = 0.1311 M

Volume of base, Vb, = 28.11 mL

Concentration of acid, Ca = ?

Volume of acid, Va + 25.0 mL

Using the formula, CaVa/CbVb = nA/nB

making Ca subject of the formula, Ca = Cb*Vb*nA/Va*nB

substituting the values into the equation

Ca = (0.1311 * 28.11 * 1) / 25.0 * 2 = 0.0737 M

Therefore, concentration of the H₂SO₄ solution is 0.0737 M

5 0
4 years ago
If a balloon is expanded from 0.055 l to 1.403 l against an external pressure of 1.02 atm, how many l⋅atm of work is done?
Ahat [919]
Work for a irreversible reaction, in thermodynamics, is calculated by multiplying the external pressure with the change in volume. Therefore,

Work = P ( V2 - V1 )
Work = 1.02 (1.403 - 0.055)
Work = 1.375 L-atm

Hope this answers the question. Have a nice day.
8 0
3 years ago
6. A student was conducting an experiment to find the volume of a spherical metal object. He placed it in the graduated cylinder
Sergio039 [100]
<h3>Answer:</h3>

                No, it wouldn't affect the volume.

<h3>Explanation:</h3>

                         Let us suppose the masses of metal object before and after shape change to be,

                              Mass before shape change  =  2.5 g

                                Mass after shape change  =  2.5 g

As the shape change has not affected on the mass so in both states it will remain 2.5 g.

Secondly, as density will remain same for both states because it is intensive property of a particular matter and is considered a characteristic property. Hence, it will also remain constant before and after shape change. Assume the density to be 2 g.mL⁻¹.

Therefore the volume calculated will be,

Before shape change:

                                   Volume-1  =  Density × Mass

                                   Volume-1  =  2 g.mL⁻¹ × 2.5 g

                                   Volume-1  =  5 mL

After shape change:

                                   Volume-2  =  Density × Mass

                                   Volume-2  =  2 g.mL⁻¹ × 2.5 g

                                   Volume-2  =  5 mL

<h3>Conclusion:</h3>

                  The volume is not affected by changing shape. Hence, after shape change the object will be having a volume of 5 mL.

8 0
4 years ago
during which of the following processes does the entropy of the system decrease? salt crystals dissolve in water air escapes fro
Nat2105 [25]
<h2>Entropy of the system decreases when methane gas and oxygen gas  combust to form carbon dioxide and water.</h2>

Explanation:

  • Salt crystals when dissolved in water the bond between the molecules of crystals are broken down increasing the movement between the atoms hence entropy is increased.
  • When air escapes from a hole in the balloon,the entropy increases as the air present inside the balloon occupies small volume as compared to outside.
  • Ice when melts at room temperature its entropy increases because the molecule in the ice are closely packed hence less movement between the molecules.
  • When water boils the kinetic energy increases or themovement between the atoms increases which increases the entropy.

Hence, the option (a), (b), (c), and (d) are not suitable to the statement                       that  "the entropy of the system decreases".

  • During combustion of methane gas there is release of carbon dioxide gas and water .Here, entropy decreases due to the formation of water which is due to overall decrease in the  kinetic energy of the system.
4 0
4 years ago
Will mark as Brainliest.
sweet-ann [11.9K]
I metals can only share electrons. Therefore they cannot bond together
6 0
3 years ago
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