Answer:
Consider how the speaker begins the speech, the support given in the body of the speech, and how the speaker concludes. Listen for changes in tone. Listen for how the speaker uses delivery techniques such as pauses, pace, voice, metaphors and symbolism, repetition and parallelism, and vocabulary.
Explanation:
Answer:
765.0 grams CuS
Explanation:
The limiting reagent is the reactant which completely reacts before the other reactant(s) is used up. When 9.0 moles Na₂S and 8.0 moles CuSO₄ react, it appears that CuSO₄ is the limiting reagent. You can tell because it results in the production of less product.
You can determine the mass of CuS by multiplying the moles by the molar mass. It is important to arrange the ratio in a way that allows for the cancellation of units.
Molar Mass (CuS): 95.62 g/mol
8.0 moles CuS 95.62 g
------------------------- x ----------------------- = 765.0 grams CuS
1 mole
Answer:
Explanation:
Temperature of gas in absolute scale T = 25 + 273 = 298 .
pressure of gas P = 1.013 x 10⁵ N / m²
density D = 1.799 kg / m³
= 1799 g / m³
From gas formula
PV / T = n R Where P is pressure , V is volume and T is absolute temperature , n is no of moles
P / T = n R / V
P / T = m R /M V where m is mass of gas and M is molecular weight .
m / V = D ( density )
P / T = DR/ M
PM / DT = R
Putting the values
1.013 x 10⁵ x 44 / (1799 x 298)
R = 8.314.09 J / K mole
Answer:
Explanation:
First of all we need to find the amount of atoms per volume (m³). We can do this using the density and the molar mass.
Now, the fraction of vacancies is equal to the N(v)/N ratio.
- N(v) is the number of vacancies
- N is the number of atoms per volume calculated above.
Therefore:
The fraction of vacancies at 600 °C will be:
I hope it helps you!
