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Nataly_w [17]
3 years ago
12

An Erlenmeyer flask containing 20.0 mL of sulfuric acid of an unknown concentration was titrated with exactly 15.0 mL of 0.25 M

NaOH solution to the second equivalence point. What was the concentration of sulfuric acid in the flask?
Chemistry
1 answer:
MrRa [10]3 years ago
8 0

Answer:

0.09375M

Explanation:

There are two methods of going about this, either we use dilution formula (easiest and fastest) or we solve through molarity.

Using dilution formula,

C2 (H2SO4) = ?

C1 (NaOH) = 0.25M

V2 (H2SO4) = 20cm³

V1 (NaOH) = 15cm³

However we can solve using molarity method

Equation of reaction =

2NaOH + H2SO4 ====》 Na2SO4 + 2H2O

O.25M of NaOH = 1000cm³

X moles = 15cm³

X = (0.25 * 15) / 1000

X = 0.00375 moles is present in 15cm³ of NaOH

From equation of reaction,

2 moles of NaOH requires 1 mole of H2SO4

Therefore

0.00375 / 2 = 0.001875 moles is present in H2SO4

From the reaction,

0.00187 moles of H2SO4 = 20 cm³

X moles = 1000cm³

X = (0.00187*1000) / 20 = 0.09375M

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2. What is the approximate mass of an atom that
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Answer:

b. 45 u

Explanation:

the mass of an atom is equal to the protons plus neutrons:

26+19=45

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3 0
3 years ago
Read 2 more answers
What is the percent composition of NaCl? Show all work please
Amiraneli [1.4K]

Answer:

NaCl = 58.44g/mol

Explanation:

Na = 22.99/58.44 × 100 = 39.33%

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7 0
3 years ago
Element X had a mass of 300g and a 1/2 life of 10 years. how many grams will remain after 40 years?
kiruha [24]
<h3>Answer:</h3>

18.75 grams

<h3>Explanation:</h3>
  • Half-life refers to the time taken by a radioactive material to decay by half of the original mass.
  • In this case, the half-life of element X is 10 years, which means it takes 10 years for a given mass of the element to decay by half of its original mass.
  • To calculate the amount that remained after decay we use;

Remaining mass = Original mass × (1/2)^n, where n is the number of half-lives

Number of half-lives = Time for the decay ÷ Half-life

                                 = 40 years ÷ 10 years

                                  = 4

Therefore;

Remaining mass = 300 g × (1/2)⁴

                            = 300 g × 1/16

                             = 18.75 g

Hence, a mass of 300 g of an element X decays to 18.75 g after 40 years.

3 0
4 years ago
What is the ratio (in the form of a decimal) of the root-mean-square speed of 238UF6 to that of 235UF6 at constant temperature?
NNADVOKAT [17]

Answer:

ratio=0.996m/s

Explanation:

RMS=\sqrt{\frac{3RT}{M} }; M= molecular weight of compound;

RMS speed is inversly proportional to the molecular weight hence compound having less molecular weight will have more rms speed value.

V1 for 238 UF_{6}; M1=238+114=352g/mole

V1 for 235 UF_{6}; M1=238+114=352g/mole

V1=\sqrt{\frac{3RT}{352} };

V2=\sqrt{\frac{3RT}{349} };

\frac{V1}{V2}=ratio of 238UF_{6} F6 to 235UF_{6}=\sqrt{\frac{349}{352} };

\frac{V1}{V2} =0.9957m/s;

\frac{V1}{V2} =0.996m/s;

4 0
3 years ago
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