We look at the criteria to select a car.
If we are not too rich, we have to bother about fuel efficiency. The mileage in terms
of km per liter or miles per gallon etc.
engine power - whether it is good enough over a slope (steep) that I may encounter
frequently with my family members.
internal space / total external size : or internal space / total price:
We find these numbers. after all , we make use of the internal space on seats.
we have to know its proportion in the total volume of the car.
the axle turning capability, wheel turning ability :
see the minimum radius and span required to turn a car in a U turn.
we have to bother about its pollution, emission level.
height / width ratio, which is important for the balance of the car.
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If we are looking at the economic point of view
monthly benefit/savings of using the car,converted into currency - Loan EMI
Answer:
.
Explanation:
Since no external force is acting on the system.
Therefore, Total energy remains constant before and after.
So, Total energy of system= energy due to potential applied+kinetic energy

(Here v=velocity ,V=potential ,q=charge and m=mass).
Putting values .
We get,
.
At point B charged particle is moving faster as compared to point A.
Hence, it is the required solution.
Explanation:
It is given that,
A helicopter blade spins at exactly 100 revolutions per minute.
Its tip is 5.00 m from the center of rotation, r = 5 m
(a) Let v is the average speed of the blade tip in the helicopter’s frame of reference. Distance covered by the helicopter, 
In 100 revolutions, 
So, average speed of the blade tip in one second is given by :


v = 52.35 m/s
(b) The average velocity over one revolution is zero because the net displacement in one rotation is 0.
Hence, this is the required solution.
Answer:
Speed acquired (Final velocity) = 12 m/s
Distance travelled = 720 meter
Explanation:
Given:
Uniform acceleration = 0.1 m/s²
Initial velocity = 0 m/s
Time taken = 2 minutes = 2 x 60 = 120 second
Find:
(a) Speed acquired (Final velocity)
(b) Distance travelled
Computation:
v = u + at
v = 0 + 0.1(120)
Speed acquired (Final velocity) = 12 m/s
Distance travelled = ut + (1/2)(a)(t²)
Distance travelled = (0)(120) + (1/2)(0.1)(120²)
Distance travelled = (1/2)(0.1)(14400)
Distance travelled = 720 meter