Answer:
decreases, increases, minimum (zero)
Explanation:
Kinetic energy of a body is directly proportional to the square of velocity of the body and the potential energy is directly proportional to the height of the body at which it is placed.
The formula for the kinetic energy is
K = 1/2 m v^2
The formula for the potential energy is
U = m g h
As the body goes up its kinetic energy decreases as the velocity of the object decreases.
As the body goes up the potential energy increases as the height increases.
At the top most point, the velocity of teh object is zero, so the kinetic energy at the top is zero.
<span>
The equation is h(t) = at^2 + vt + d
where a = acceleration of gravity = - 32.174 ft/sec^2
v = 25 feet/sec
d = starting height = 0
and h(t) = 0 when the ball hits the ground.
So, 0 = - 32.174t^2 + 25t + 0
You can use the quadratic formula on that if you want, or you can solve like this:
0 = - 32.174t^2 + 25t
0 = t ( -32.174t + 25)
So, one solution of that is t = 0, corresponding to the initial time when the ball is kicked.
The other time is: 25 = 32.174t
t = 25/32.174 = 0.777 seconds
or approximately 0.8 seconds.</span>
Answer:
T= 8.061N*m
Explanation:
The first thing to do is assume that the force is tangential to the square, so the torque is calculated as:
T = Fr
where F is the force, r the radius.
if we need the maximum torque we need the maximum radius, it means tha the radius is going to be the edge of the square.
Then, r is the distance between the edge and the center, so using the pythagorean theorem, r i equal to:
r = 
r = 0.5374m
Finally, replacing the value of r and F, we get that the maximun torque is:
T = 15N(0.5374m)
T= 8.061N*m
I think is a high-pressure system because it is only in one particular area.
Answer:
The electrical loads in parallel circuits each have the same voltage drop, with equals the total applied voltage of the circuit.
Explanation:
I did some research and the voltage drop across any branch of a parallel circuit is the same as the applied voltage.
