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3 years ago

Explain how a step-down transformer makes electricity safe for use in homes.

Physics

2 answers:

notka56 [123]3 years ago

5 0

Answer:

Sample Response: High-voltage current enters the primary winding, which induces a magnetic field in the core. The magnetic field induces a current in the secondary winding. The voltage in the secondary winding is lower because it has fewer coils than the primary winding.

Explanation

Savatey [412]3 years ago

3 0

Answer:

it lowers the voltage in homes

Explanation:

this is due to safety reasons as a human cant survive power line voltages which are between 150k and 760k and if you plugged anything short of a piece of 1 inch thick wire not counting insulation it would immediately start smoking and burn the cable.

You might be interested in

It is known that the gravitational force of attraction between two alpha particles is much weaker than the electrical repulsion.

natali 33 [55]

Answer:

The ratio of gravitational force to electrical force is 3.19 x 10^-36

Explanation:

mass of an alpha particle = 6.64 x $10^{-27}$ kg

charge on an alpha particle = +2e = +2(1.6 x $10^{-19}$ C) = 3.2 x $10^{-19}$ C

distance between particles = d

For gravitational attraction:

The force of gravitational attraction F = $\frac{Gm^{2} }{r^{2} }$

where G = gravitational constant = 6.67 x $10^{-11}$ m^3 kg^-1 s^-2

r = the distance between the particles = d

m = the mass of each particle

therefore, gravitational force = $\frac{6.67*10^{-11}*(6.64*10^{-27} )^{2} }{d^{2} }$ = $\frac{2.94*10^{-63} }{d^{2} }$ Newton

For electrical repulsion:

Electrical force between the particles = $\frac{-kQ^{2} }{r^{2} }$

where k is the Coulomb's constant = 9.0 x $10^{9}$ N•m^2/C^2

r = distance between the particles = d

Q = charge on each particle

therefore, electrical force = $\frac{-9*10^{9}*(3.2*10^{-19} )^{2} }{d^{2} }$ = $\frac{-9.216*10^{-28} }{d^{2} }$ Newton

the negative sign implies that there is a repulsion on the particles due to their like charges.

Ratio of the magnitude of gravitation to electrical force = $\frac{2.94*10^{-63} }{9.216*10^{-28} }$

==> 3.19 x 10^-36

8 0

3 years ago

the pull of gravity on mars is 3.7m/s^2. if a astronaut on mars lifts a 10 kg rock 1 m off the ground, just to see whats under i

Elanso [62]

Gravitational potential energy can be calculated using the formula:

$PE_{grav} =mgh$

Where:
PEgrav = Gravitational potential energy
m= mass
g = acceleration due to gravity
h = height

On Earth acceleration due to gravity is a constant 9.8 but since the scenario is on Mars, the pull of gravity is different. In this case, it is 3.7, so we will use that for g.

So put in what you know and solve for what you don't know.
m = 10kg
g = 3.7m/s^2
h = 1m

So we put that in and solve it.
$PE_{grav} =mgh$
$PE_{grav} =(10kg)(3.7m/s^{2})(1m)$
$PE_{grav} =37J$

7 0

4 years ago

Jake calculates that the frequency of a wave is 500 hertz and that the wave is moving at 1,250 m/s. What is the wavelength of th

Neko [114]

Frequency (f) = 500 hz (SI)
Velocity (V) = 1250 m/s (SI)
Wavelength (Lambda) = ? meters

$v = \lambda \times f$
$1250 = \lambda \times 500 \\ \lambda = 1250 \div 500 \\ \lambda = 2.5 \: meters$

6 0

3 years ago

QUESTION:

vampirchik [111]

Answer:

I don't know why you are asking me?

5 0

3 years ago

How long would it take 2.0x10^20 electrons to pass through a point in a conductor if the current was 10.0A?

inysia [295]

1 coulomb of electric charge is carried by 6.25 x 10^18 electrons

1 Ampere = 1 coulomb per second
10 A = 10 coulombs per second

(2.0 x 10^20 electrons) x (coul / 6.25 x 10^18 electrons) / (10 coul/sec) =

(2.0 x 10^20) / (6.25 x 10^18 x 10) sec = 3.2 seconds

6 0

3 years ago