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notka56 [123]
4 years ago
6

A conducting sphere contains positive charge distributed uniformly over its surface. Which statements about the potential due to

this sphere are true?
A) The potential at the center of the sphere is zero.
B) The potential is lowest, but not zero, at the center of the sphere.
C) The potential at the center of the sphere is the same as the potential at the surface.
D) The potential at the center is the same as the potential at infinity.
E) The potential at the surface is higher than the potential at the center.
Physics
1 answer:
user100 [1]4 years ago
5 0
The correct answer is C. The potential at the center of the sphere is the same as
the potential at the surface
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Consider a mass initially moving at 7.50 m/s. How does it take to move 3.5 km (Be sure to convert to meters) if it accelerates a
Tomtit [17]
The mass is moving by uniformly accelerated motion, with initial velocity v_i=7.50 m/s and acceleration a=0.55 m/s^2. Its position at time t is given by the following law:
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where we take the initial position x_i=0 since we are only interested in the distance traveled by the mass.

If we put x(t)=d=3.5 km=3500 m into the equation, the corresponding time t is the time it takes for the mass to travel this distance:
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4 years ago
You look in the sky and see two jetliners that you know are of equal size, yet one appears to be much larger. Because of your kn
Ksju [112]

Answer:

Because of the knowledge of <u>relative size</u>, it will be assumed that the smaller jetliner is farther away.

Explanation:

According to the theory of relative size, the distance that an object has to the viewing individual affects the perception of the individual regarding the size of the object.

As stated in this case, one of the jetliners is farther away from the other. Therefore, even if the jets are of equal size, the one that is at a greater distance is perceived to be smaller as it is at a greater viewing range. The one that is nearer to the individual seems bigger in comparison to the one farther away due to a closer viewing range.

Therefore, the jet that is nearer appears larger.

To know more about relative size, refer to:

brainly.com/question/19998265

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8 0
2 years ago
2 Resistors of resistance, R = (100 +- 3) Ohm, R2 = (200+-4)Ohm are connected in Parallel and Series.
Orlov [11]

According to what I've learnt, in any expression of multiplication or division, the percentage errors of each term are added up to find the equivalent percentage error. That is, if

<span><span>y=<span>ABC
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For the above problem, let <span><span>Rs</span></span> denote series combination. Then <span><span><span>Rs</span>=300±7</span></span> ohm.

Let <span><span>Rp</span></span> denote parallel combination.

<span><span>∴<span>Rp</span>=<span><span><span>R1</span><span>R2/</span></span><span><span>R1</span>+<span>R2 </span></span></span>= <span><span><span>R1</span><span>R2/</span></span><span>Rs</span></span></span></span>

Ignoring errors, we get <span><span><span>Rp</span>=<span>200/3 = </span></span></span><span><span>66.67</span></span> ohm

<span><span>%<span>error in R1</span>=3</span></span>, <span><span>%<span>error in R2</span>=2</span></span>, <span><span>%<span>error in Rs</span>=<span>7/3</span></span></span>

Hence, <span><span>%<span>error in Rp</span>=3+2+<span>7/3</span>=<span>22/3</span></span></span>

So, error in <span><span>Rp</span></span> will be <span><span><span>22/3</span>% of </span></span><span><span>200/3</span></span>, which is approximately <span>4.89.</span>

Hence, I got <span><span><span>Rp</span>=66.67±4.89</span></span> ohm.

However, the book used the formula described and proved here and arrived at the answer <span><span><span>Rp</span>=66.67±1.8</span></span>ohm.

8 0
3 years ago
Read 2 more answers
a person expended 500 newtons to move a full wheelbarrow 30 meters how much work was done? a person expended 500 newtons to move
stiv31 [10]
<span>A person expended 500 newtons to move a full wheelbarrow 30 meters how much work was done?

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6 0
3 years ago
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kirza4 [7]

Explanation:

Bonjour , pourriez-vous m'aider à faire cet exercice svp ??

a) Convertir les longueurs suivantes en utilisant les puissances de 10.

1,7 cm en mètre

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49 mm en mètre

35 m en centimètre

63 km en mètre

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b) Ecrire les longueurs ainsi converties en utilisant la notation scientifique

4 0
3 years ago
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