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lina2011 [118]
2 years ago
8

What is the following quotient?

Mathematics
1 answer:
Sergio039 [100]2 years ago
3 0

Answer:

\frac{\sqrt{3} }{4}

Step-by-step explanation:

\frac{1}{1+\sqrt{3} }

basically we want to get rid of the √3 on the denominator

to do so we multiply it by itself so it is a perfect square

but whatever we do to the top we must do to the bottom so we multiply the numerator and denominator by √3

\frac{1*\sqrt{3} }{1+\sqrt{3}*\sqrt{3}  }=\frac{\sqrt{3} }{1+\sqrt{9} } =\frac{\sqrt{3} }{1+3} =\frac{\sqrt{3} }{4}

notes : √3 × √3 = √9 which is a perfect square that simplfies to 3

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Step-by-step explanation:

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<em>N</em><em>o</em><em>t</em><em>e</em><em>:</em><em> </em><em>2</em><em>y</em><em>^</em><em>0</em><em> </em><em>=</em><em> </em><em>2</em><em>(</em><em>y</em><em>^</em><em>0</em><em>)</em><em> </em><em>=</em><em> </em><em>2</em><em>(</em><em>1</em><em>)</em><em> </em><em>=</em><em> </em><em>2</em><em> </em><em>w</em><em>h</em><em>e</em><em>r</em><em>e</em><em>a</em><em>s</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>(</em><em>2</em><em>y</em><em>)</em><em>^</em><em>0</em><em> </em><em>=</em><em> </em><em>1</em>

6 0
3 years ago
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