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Veronika [31]
2 years ago
8

Let’s take the case of the 4-kg block with an initial velocity of 10 m/s that is colliding with a 6-kg block that is stationary.

After the collision, both blocks are stuck together and are moving together as one. Determine the velocity of the linked blocks after the collision.
Physics
2 answers:
Aleksandr [31]2 years ago
8 0

Answer:

6kg ise yes...............

DiKsa [7]2 years ago
8 0

\\ \rm\Rrightarrow m1v1+m2v2=(m1+m2)v_3

\\ \rm\Rrightarrow 4(10)+6(0)=(6+4)V3

\\ \rm\Rrightarrow 40=10v3

\\ \rm\Rrightarrow V3=4m/s

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A block mass m (0.25 kg) is pressed against (but is not attached to) an ideal spring of force constant k (100 N/m) and negligibl
VMariaS [17]

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d. All the above choices are correct.

Explanation:

When a spring of spring constant k is compressed by distance x , the potential energy stored in it is equal to

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In the second case ,

energy acquired by box becomes  two times

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