Question

Let’s take the case of the 4-kg block with an initial velocity of 10 m/s that is colliding with a 6-kg block that is stationary. After the collision, both blocks are stuck together and are moving together as one. Determine the velocity of the linked blocks after the collision.

Answer 1

Answer:

6kg ise yes...............

Answer 2

$\\ \rm\Rrightarrow m1v1+m2v2=(m1+m2)v_3$

$\\ \rm\Rrightarrow 4(10)+6(0)=(6+4)V3$

$\\ \rm\Rrightarrow 40=10v3$

$\\ \rm\Rrightarrow V3=4m/s$