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Alexus [3.1K]
3 years ago
8

A tungsten wire has resistance R at 20°C. A second tungsten wire at 20°C has twice the length and half the cross-sectional area

of the first wire. In terms of R, the resistance of the second wire is
(1)R/2
(2)2R
(3)R
(4)4R
Physics
1 answer:
Bad White [126]3 years ago
6 0
The resistance is 4 times the resistance of the first wire. the formula is R = p*l/A with p being resistivity, l length and A area. So if you double length and half area, which botv result in more resistance, you get p*2/0.5 or 4 (p can be abandoned because it is the same. We take standard length and area as 1)
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The tortoise and the hare are having a race over a course of length 0.52 km. The tortoise crawls along at a constant 0.075 m/s w
EastWind [94]

Answer:the hare slept for 1 hr 55minutes.

Explanation: distance is changed to meters = 520m

Speed=distance/time

Speed of tortoise is 0.075m/s=520m/t

Crops multiplying t= 520/0.075 = 6933.3 seconds.

Speed for hare 16.7m/s =260m/t

ie 260m is half of the distance.

t =15.56seconds

Therefore the time slept by the hare = 6933.3- 15.56= 6917.74 seconds.

Converting to hours = 1hr. 55minutes is the time the hare slept.

3 0
3 years ago
What is the magnitude of the final velocity of the combined cars?
Alinara [238K]
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nikklg [1K]
The atmosphere....................................
4 0
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Identify the arrows that show the correct direction of heat transfer.
allochka39001 [22]

Answer:

arrow from liquid to atmosphere is correct

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arrow from beaker to atmosphere is correct

Explanation:

heat always flows from direction of higher to lower direction of temperature.

let the temperature of atmosphere be 66 F, beaker be 112 F, liquid be 98 F.

arrow from liquid to atmosphere is correct because heat flows from 98 F to 66 F.

arrow from atmosphere to beaker must be reversed because heat must flow from 112 F to 66 F.

arrow from beaker to atmosphere is correct as heat flows from 112 F to 66 F.

arrow from liquid to beaker must be reversed as heat flows from 112 F to 98 F.

8 0
4 years ago
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Brut [27]

Explanation:

According to the figure,

                    \vec{p} = q\vec{d}

Formula to calculate net dipole moment is as follows.

          \vec{p_{net}} = 2P Cos 52^{o}\hat{i} + (0)\hat{j}

           \vec{p_{net}} = 2qd Cos 52^{o}\hat{i}

                        = 2 \times 1.6 \times 10^{-19} \times 0.958 \times 10^{-10} \times Cos 52^{o}\hat{i}

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Therefore, we can conclude that the net dipole moment for given water molecule is 1.88 \times 10^{-29}\hat{i} C-m.

5 0
4 years ago
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