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Darya [45]
3 years ago
14

A block mass m (0.25 kg) is pressed against (but is not attached to) an ideal spring of force constant k (100 N/m) and negligibl

e mass, compressing the spring a distance 0.1 m. After it is released, the box slides along a leveled surface for 2 m before fully stops. If we repeat this experiment but instead use a spring having force constant 2k,
a. the box will go up the incline twice as high as before.
b. just as it moves free off the spring, the kinetic energy of the box will be twice as great as before.
c. just as it moves free off the spring, the speed of the box will be
d. All the above choices are correct.
e. None of the above choices are correct.
Physics
1 answer:
VMariaS [17]3 years ago
5 0

Answer:

d. All the above choices are correct.

Explanation:

When a spring of spring constant k is compressed by distance x , the potential energy stored in it is equal to

E = 1/2 k x²

If spring constant is 2 k , potential energy stored

E = 1/2 2k x²

= k x²

which is twice the earlier potential energy.

In the first case , the energy of spring is imparted to box . The energy given to box is spent by frictional force due to which box comes to rest.

So energy of box acquired from spring = work done by frictional force.

So energy of box acquired from spring =  F X d  , F is frictional force , d is displacement .

In the second case ,

energy acquired by box becomes  two times

Work done by frictional force will also become two times to put box at rest

So displacement will be two times ( because frictional force is constant )

so option a is correct .

option b is also correct .

Because kinetic energy  of box will be twice as explained above .

So option d will be correct.

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Alchen [17]

The new speed of car is 10.9 m/s

<h3 />

According to the principle of momentum conservation, momentum is only modified by the action of forces as they are outlined by Newton's equations of motion; momentum is never created nor destroyed inside a problem domain.

Mass of the railroad car, m₁ = 7950 kg

Mass of the load, m₂ = 2950 kg

It can be assumed as the speed of the car, u₁ = 15 m/s

Initially, it is at rest, u₂ = 0

Let v is the speed of the car. It can be calculated using the conservation of momentum as :

m_1u_1 + m_2u_2 = (m_1 + m_2) v

v =\frac{m_1u_1}{m_1+m_2}

v = \frac{7950*15}{7950+2950}

v= 10.9 m/s

Therefore, the new speed of care is 10.9 m/s

Learn more about momentum here:

brainly.com/question/22257327

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5 0
2 years ago
What is the elevation of point B?<br> What about F?
kolbaska11 [484]

Explanation:

Since I can only do this by observation, the elevation of F is approximately 850km and the elevation of B is 925km.

7 0
3 years ago
20. The speed of Light is 3.0 x 108 m/s. Blue Light has a frequency of 6.11 x 1014 Hz. What is its wavelength?
Sladkaya [172]

Answer:

4.91 x 10⁻⁷ m

Explanation:

the applicable formula is

v = fλ

where

v = velocity (i.e speed) = given as 3.0 x 10⁸ m/s

f = frequency = given asw 6.11 x 10¹⁴

λ = wavelength

if we rearrange the equation and substitute the values given above,

v = fλ

λ = v/f  

= 3.0 x 10⁸ / 6.11 x 10¹⁴

= 4.91 x 10⁻⁷ m

5 0
3 years ago
A certain lightning bolt moves 10.0 C of charge. How many charges have been moved if the fundamental unit of charge is 1.6 x 10-
Andrej [43]

To solve this problem, use the ratio given by the total number of electrons or protons that exist as a function of the total charge, and inversely proportional to the value of the fundamental charge. The number of fundamental unit  |q_e| that constitutes a charge of 40.0C can be calculated as

N = \frac{|Q|}{|q_e|}

Here,

q_e = Value of charge and it is the fundamental charge

Q = Total Charge

N = Total number of electron or protons

The number of fundamental units is calculated as follows

N = \frac{10.0C}{1.6*10^{-19}C}

N = 6.25*10^{19}

Therefore the number of fundamental charge units moved by lightning bolt is 6.25*10^{19}

8 0
3 years ago
A liquid has a volume of 100 cm and a mass of 85g.
djyliett [7]

Answer:

B. Its density is lower than that of water

Explanation:

density = mass / volume

density of the liquid = 85 / 100 = 0.85 g/cm^3

now,

density of water is 1 g/cm^3 which is greater than the density of the given liquid ( 0.85 g/cm^3 )

6 0
2 years ago
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